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尝试使用路标 oauth 库从 android 客户端调用。我生成了新的 APIv2 密钥,但似乎没有什么不同。我得到的错误看起来像:

{"error":{"text":"Signature was 
invalid","id":"INVALID_SIGNATURE","description":"Invalid signature. 
Expected signature base string: GET&http%3A%2F%2Fapi.yelp.com 
%2Fv2%2Fsearch&category_filter%3Drestaurants%2520food%26limit%3D10%26ll 
%3D37.422005%252C-122.084095%26oauth_consumer_key 
%3DPbSjw9p08To_XXXXXXXXZg%26oauth_nonce 
%3D-81097XXXXXXXX560239%26oauth_signature_method%3DHMAC- 
SHA1%26oauth_timestamp%3D129XXXX091%26oauth_token 
%3DARfbDXXXXXXXXlBHARTgygLkcMw9h8eW%26oauth_version%3D1.0%26offset 
%3D0%26radius_filter%3D300%26sort%3D0"}} 

我仔细检查了一下,我所有的令牌和秘密值都与管理 API 屏幕中的内容完全匹配。代码当前如下所示:

if (location != null) { 
        String lat = Double.toString(location.getLatitude()); 
        String lng = Double.toString(location.getLongitude()); 
        String category = "restaurants+food"; 
        String radius = "300"; 
        String limit = "10"; 
        String offset = "0"; 
        String sort = "0"; 
        try { 
                String query = String.format("http://api.yelp.com/v2/search?ll=%s, 
%s&category_filter=%s&radius_filter=%s&limit=%s&offset=%s&sort=%s", 
                                URLEncoder.encode(lat, ENCODING_SCHEME), 
                                URLEncoder.encode(lng, ENCODING_SCHEME), 
                                category, 
                                URLEncoder.encode(radius, ENCODING_SCHEME), 
                                URLEncoder.encode(limit, ENCODING_SCHEME), 
                                URLEncoder.encode(offset, ENCODING_SCHEME), 
                                URLEncoder.encode(sort, ENCODING_SCHEME)); 
                OAuthConsumer consumer = new CommonsHttpOAuthConsumer(CONSUMER_KEY, 
CONSUMER_SECRET); 
                consumer.setTokenWithSecret(TOKEN, TOKEN_SECRET); 
                consumer.setMessageSigner(new HmacSha1MessageSigner()); 
                consumer.setSendEmptyTokens(true); 
                consumer.setSigningStrategy(new QueryStringSigningStrategy()); 
                String signedQuery = consumer.sign(query); 
                Log.i(getClass().getName(), signedQuery); 
                HttpGet request = new HttpGet(signedQuery); 
                HttpClient httpClient = new DefaultHttpClient(); 
                HttpResponse response = (HttpResponse) httpClient.execute(request); 
                HttpEntity entity = response.getEntity(); 
                String jsonResult = EntityUtils.toString(entity); 
                Log.i(getClass().getName(), jsonResult); 
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1 回答 1

2

才发现问题。您应该在设置 TokenSecret 之前添加 MessageSigner,否则它为空并且所有内容都被错误地签名

于 2011-07-08T18:52:44.977 回答