我只是在查看 django，并试图通过id作为参数传递给 URL来列出书籍books/urls.py。但是找不到 404 页面错误。当我在浏览器中输入此 url 时，我没有得到 url 中的错误：
http://192.168.0.106:8000/books/list/21/
书店/urls.py
urlpatterns = [
path('admin/', admin.site.urls),
path('books/', include("books.urls"))
]
设置.py
INSTALLED_APPS = [
'django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
'books'
]
...
...
...
ROOT_URLCONF = 'bookstore.urls'
书籍/urls.py
urlpatterns = [
path('home/', create),
path('list/(?P<id>\d+)', list_view),
]
书籍/views.py
def create(request):
form = CreateForm(request.POST or None, request.FILES or None)
if form.is_valid():
instance = form.save(commit=False)
instance.save()
messages.success(request, "Book Created")
return redirect('/books/list', kwargs={"id":instance.id})
return render(request, "home.html", {"form":form})
def list_view(request, id=None):
books = Book.objects.filter(id=id)
return render(request, "list.html", {"books": books})
项目结构：
├── books
│ ├── admin.py
│ ├── forms.py
│ ├── __init__.py
│ ├── models.py
│ ├── urls.py
│ └── views.py
├── bookstore
│ ├── __init__.py
│ ├── settings.py
│ ├── urls.py
这是屏幕截图 -
编辑 - 如评论中所述 - 尝试通过附加但没有运气/的 url 表达式books.urls:(
