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我正在使用 Report builder 2008 处理 ssrs 报告,目前正在尝试使用类似的东西进行连接,但是当我这样做时,我收到字段“lifeamount”的错误,指定表达式只能引用当前数据集中的字段范围。我尝试了不同的方法来指定所有字段都相同的数据集,但无济于事。这甚至可能吗?

=rtrim(First(Fields!FRSTNAME.Value,"EmployeeInfo")) & " " & rtrim(First(Fields!MIDLNAME.Value, "EmployeeInfo")) & " " & rtrim(First(Fields!LASTNAME.Value, "EmployeeInfo")) & " " & IIF((Fields!Lifeamount.Value)> 100000.00, 100000.00, Fields!lifeamount.value, "EmployeeInfo"))

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2 回答 2

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SSRS 表达式区分大小写,这意味着您的第二个lifeamount引用很可能是错误的。

试试这个:

=rtrim(First(Fields!FRSTNAME.Value,"EmployeeInfo")) & " " &
rtrim(First(Fields!MIDLNAME.Value, "EmployeeInfo")) & " " &
rtrim(First(Fields!LASTNAME.Value, "EmployeeInfo")) & " " &
IIF((Fields!Lifeamount.Value)> 100000.00, 100000.00, Fields!Lifeamount.value, "EmployeeInfo"))
于 2017-11-16T15:13:23.977 回答
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如果表达式位于与您正在获取的详细信息(即“EmployeeInfo”)相同范围内的单元格中,那么我认为您根本不需要指定它。

我认为还有一些括号不合适。我目前无法测试它,但试试这个......

=rtrim(First(Fields!FRSTNAME.Value,"EmployeeInfo")) & " " & 
rtrim(First(Fields!MIDLNAME.Value, "EmployeeInfo")) & " " &
rtrim(First(Fields!LASTNAME.Value, "EmployeeInfo")) & " " &
IIF((Fields!Lifeamount.Value, "EmployeeInfo")> 100000.00, 100000.00, (Fields!Lifeamount.value, "EmployeeInfo"))
于 2017-11-16T15:28:23.703 回答