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使用基本运算符,导出附加运算符交集。
R ∩ S = ?
我认为可能是: (R ∪ S) - ((R -S) ∪ (S -R)) 但我也认为可能有更简单的方法吗?
A 与 B 相交等于 A - (A - B) 或等价于 B - (B - A)
R ∩ S也等于~( (~R) ∪ (~S) )
R ∩ S
~( (~R) ∪ (~S) )
~A的补码在哪里A
~A
A