我一直在使用此处的代码将三位数字转换为条形码，以便在我工作的公司进行扫描。
我只发现一个条形码有问题。当它编码“002”时，它输出“Ì002 Δ。我发现这不会与空间一起扫描。花费大量时间搜索和寻找该空间中应该包含的内容以及扫描的内容。我发现这里的条形码生成器代码具有  作为校验字符。
现在我的问题是如何更改代码以正确编码？或者，我可以实施另一个免费代码示例来获取代码 128 条码吗？
我已经实现了
MEKBarcodeLBL.Text = HazmatLabels.Classes.BarcodeConverter128.StringToBarcode(MEKScrapLBL.Text).PadLeft(3, '0');
提前感谢您的所有帮助！！！！
BarcodeConverter128.cs
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
namespace HazmatLabels.Classes
{
/// <summary>
/// Code 128
/// Convert an input string to the equivilant string including start and stop characters.
/// This object compresses the values to the shortest possible code 128 barcode format
/// </summary>
public static class BarcodeConverter128
{
/// <summary>
/// Converts an input string to the equivilant string, that need to be produced using the 'Code 128' font.
/// </summary>
/// <param name="value">String to be encoded</param>
/// <returns>Encoded string start/stop and checksum characters included</returns>
public static string StringToBarcode(string value)
{
// Parameters : a string
// Return : a string which give the bar code when it is dispayed with CODE128.TTF font
// : an empty string if the supplied parameter is no good
int charPos, minCharPos;
int currentChar, checksum;
bool isTableB = true, isValid = true;
string returnValue = string.Empty;
if (value.Length > 0)
{
// Check for valid characters
for (int charCount = 0; charCount < value.Length; charCount++)
{
//currentChar = char.GetNumericValue(value, charPos);
currentChar = (int)char.Parse(value.Substring(charCount, 1));
if (!(currentChar >= 32 && currentChar <= 126))
{
isValid = false;
break;
}
}
// Barcode is full of ascii characters, we can now process it
if (isValid)
{
charPos = 0;
while (charPos < value.Length)
{
if (isTableB)
{
// See if interesting to switch to table C
// yes for 4 digits at start or end, else if 6 digits
if (charPos == 0 || charPos + 4 == value.Length)
minCharPos = 4;
else
minCharPos = 6;
minCharPos = BarcodeConverter128.IsNumber(value, charPos, minCharPos);
if (minCharPos < 0)
{
// Choice table C
if (charPos == 0)
{
// Starting with table C
returnValue = ((char)205).ToString(); // char.ConvertFromUtf32(205);
}
else
{
// Switch to table C
returnValue = returnValue + ((char)199).ToString();
}
isTableB = false;
}
else
{
if (charPos == 0)
{
// Starting with table B
returnValue = ((char)204).ToString(); // char.ConvertFromUtf32(204);
}
}
}
if (!isTableB)
{
// We are on table C, try to process 2 digits
minCharPos = 2;
minCharPos = BarcodeConverter128.IsNumber(value, charPos, minCharPos);
if (minCharPos < 0) // OK for 2 digits, process it
{
currentChar = int.Parse(value.Substring(charPos, 2));
currentChar = currentChar < 95 ? currentChar + 32 : currentChar + 100;
returnValue = returnValue + ((char)currentChar).ToString();
charPos += 2;
}
else
{
// We haven't 2 digits, switch to table B
returnValue = returnValue + ((char)200).ToString();
isTableB = true;
}
}
if (isTableB)
{
// Process 1 digit with table B
returnValue = returnValue + value.Substring(charPos, 1);
charPos++;
}
}
// Calculation of the checksum
checksum = 0;
for (int loop = 0; loop < returnValue.Length; loop++)
{
currentChar = (int)char.Parse(returnValue.Substring(loop, 1));
currentChar = currentChar < 127 ? currentChar - 32 : currentChar - 100;
if (loop == 0)
checksum = currentChar;
else
checksum = (checksum + (loop * currentChar)) % 103;
}
// Calculation of the checksum ASCII code
checksum = checksum < 95 ? checksum + 32 : checksum + 100;
// Add the checksum and the STOP
returnValue = returnValue +
((char)checksum).ToString() +
((char)206).ToString();
}
}
return returnValue;
}
private static int IsNumber(string InputValue, int CharPos, int MinCharPos)
{
// if the MinCharPos characters from CharPos are numeric, then MinCharPos = -1
MinCharPos--;
if (CharPos + MinCharPos < InputValue.Length)
{
while (MinCharPos >= 0)
{
if ((int)char.Parse(InputValue.Substring(CharPos + MinCharPos, 1)) < 48
|| (int)char.Parse(InputValue.Substring(CharPos + MinCharPos, 1)) > 57)
{
break;
}
MinCharPos--;
}
}
return MinCharPos;
}
}
}