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我正在尝试在运行我的 phpunit 测试时从 php 代码运行夹具命令。它最终出现以下错误: Symfony\\Component\\Console\\Exception\\CommandNotFoundException] There are no commands defined in the \u0022doctrine:fixtures

我必须说我一直在我的控制器上运行相同的东西并且它运行良好。它不仅找不到doctrine:fixtures命令,而且找不到所有其他命令。

就好像在运行测试时所有命令都无法访问。

这是我的代码:

namespace tests\functional\User\ManagerBundle\Controller;    

use Symfony\Bundle\FrameworkBundle\Test\WebTestCase;
use Symfony\Component\HttpFoundation\JsonResponse;
use Symfony\Component\Console\Input\ArrayInput;
use Symfony\Component\Console\Application;
use Symfony\Component\Console\Output\BufferedOutput;

class ClassControllerTest extends WebTestCase
{
   protected function setUp()
   {
        $client = static::createClient();

        $application = new Application($client->getKernel());
        $application->setAutoExit(false);

        $input = new ArrayInput(array(
            'command' => 'doctrine:fixtures:load',
            // (optional) define the value of command arguments
//            'fooArgument' => 'barValue',
            // (optional) pass options to the command
            '--no-interaction' => true,
            '--env' => 'TEST'
        ));

        // You can use NullOutput() if you don't need the output
        $output = new BufferedOutput();
        $application->run($input, $output);

        // return the output, don't use if you used NullOutput()
        $content = $output->fetch();

        var_dump(new JsonResponse($content));

   }
}
4

1 回答 1

3

简单的回答:

我不得不使用以下语句

use Symfony\Bundle\FrameworkBundle\Console\Application;

代替

use Symfony\Component\Console\Application;
于 2017-11-06T16:36:30.730 回答