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我正在使用 Hibernate 4.3.1 通过使用具有匹配数据的列从四个不同的不相关表中获取记录。为此，我编写了一个查询，如下所示

SELECT ca.csc_issuer_id as cssIssuerId,
       ca.csc_serial_number as cssSerialNumber,
       ca.csc_type as cssType,
       ca.csc_lifecycle_count as cssLifecycleCount,
       aa.app_provider_id as ...,
       aa.provider_app_serial_number as ...,
       aa.card_app_serial_number as ..,
       aa.app_type as ..,     
       pa.csc_issuer_id as ..,
       pa.csc_serial_number as ..,
       pa.prodType  
  FROM AATable AA, CATable CA, PATable PA          
 WHERE AA.CSC_SERIAL_NUMBER = CA.CSC_SERIAL_NUMBER 
       AND AA.CSC_SERIAL_NUMBER = PA.CSC_SERIAL_NUMBER
       AND AA.CSC_SERIAL_NUMBER = 123456
       AND AA.csc_issuer_id = 26
       AND AA.csc_type = 1
       AND AA.csc_lifecycle_count = 0
       AND PA.app_provider_id = 26
       AND PA.provider_app_serial_number = 123456
       AND PA.card_app_serial_number = 0

当我直接在 Oracle 数据库上运行此查询时，它返回 3 行（所有这些显然都匹配所有 where 条件，但每一行都有不同的 PATable.prodType 列的值）但是当我在我的 java 代码中使用它时，Hibernate 只返回一行是 SQL 返回的第一行。知道发生了什么吗？我尝试过加入表格，但结果相同。

@AllArgsConstructor
@NoArgsConstructor
@Getter
@Setter
@Builder
public class MyPOJO {
private Long cssIssuerId;
private Long cssSerialNumber
other members....
}
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