5

我有一个文件，其中包含：

VoicemailButtonTest
VoicemailButtonTest
VoicemailButtonTest
VoicemailButtonTest
VoicemailButtonTest
VoiceMailConfig60CharsTest
VoicemailDefaultTypeTest
VoiceMailIconSelectableTest
VoiceMailIconSelectableTest
VoiceMailIconSelectableTest
VoiceMailIconSelectableTest
VoiceMailIconSelectableTest
VoicemailSettingsFromMessageModeScreenTest
VoicemailSettingsFromMessageModeScreenTest
VoicemailSettingsTest
VoicemailSettingsTest
VoicemailSettingsTest
VoicemailSettingsTest
VoicemailSettingsTest
VoicemailSettingsTest
VoicemailSettingsTest

如何用计数替换重复的行：

VoicemailButtonTest (5)
VoiceMailConfig60CharsTest (1)
VoicemailDefaultTypeTest (1)
VoiceMailIconSelectableTest (5)
VoicemailSettingsFromMessageModeScreenTest (2)
VoicemailSettingsTest (7)

我将这对放入关联数组中。我尝试在“while”语句中使用“read”，但数组丢失了。这是我的尝试：

unset line
tests=$(cat file.log)
echo "$tests" | 
    while read l; do 
        if [ "$l" == "${line}" ]; then
            let cnt++;
        else
            echo "${line} (${cnt})"
            line=${l}
            cnt=1
        fi
        export run_suites
    done
4

6 回答 6

5

假设输出的格式不必完全匹配

VoicemailButtonTest (5)
VoiceMailConfig60CharsTest (1)
VoicemailDefaultTypeTest (1)
VoiceMailIconSelectableTest (5)
VoicemailSettingsFromMessageModeScreenTest (2)
VoicemailSettingsTest (7)

你可以使用

sort <input_file> | uniq -c

如果您需要输出与您发布的内容完全匹配，您可以使用

awk '{duplicates[$1]++} END{for (ind in duplicates) {print ind,"("duplicates[ind]")"}}' <input_file>

编辑：在 anubhava 的回答之后发布......但由于添加了 sort 命令而离开（除非人们建议我删除）。

于 2017-10-31T18:44:30.037 回答
3

您可以使用这个简单的 awk 脚本来获取计数：

awk '{freq[$1]++} END{for (i in freq) print i, "(" freq[i] ")"}' file

VoiceMailConfig60CharsTest (1)
VoicemailSettingsFromMessageModeScreenTest (2)
VoiceMailIconSelectableTest (5)
VoicemailButtonTest (5)
VoicemailDefaultTypeTest (1)
VoicemailSettingsTest (7)

如果要保持输入中出现的顺序，请使用：

awk '!freq[$1]++{order[++k]=$1} END{
    for (i=1; i<=k; i++) print order[i], "(" freq[order[i]] ")"}' file

VoicemailButtonTest (5)
VoiceMailConfig60CharsTest (1)
VoicemailDefaultTypeTest (1)
VoiceMailIconSelectableTest (5)
VoicemailSettingsFromMessageModeScreenTest (2)
VoicemailSettingsTest (7)
于 2017-10-31T18:37:32.127 回答
3

如果您不关心确切的输出格式，只需使用sortand uniq：

$ sort file.log | uniq -c
5 VoicemailButtonTest
1 VoiceMailConfig60CharsTest
1 VoicemailDefaultTypeTest
5 VoiceMailIconSelectableTest
2 VoicemailSettingsFromMessageModeScreenTest
7 VoicemailSettingsTest

sort，当然，如果文件已经按照您的问题排序，则没有必要。如果它没有被排序，uniq -c它仍然可以工作，但是如果它与前一行相同，它只会认为该行是重复的：

$ printf 'a\nb\na' | uniq -c
1 a
1 b
1 a
于 2017-10-31T18:44:42.610 回答
1 
$ awk '$1 != prev{if (NR>1) print prev, "("cnt")"; prev=$1; cnt=0} {cnt++} END{print prev, "("cnt")"}' file
VoicemailButtonTest (5)
VoiceMailConfig60CharsTest (1)
VoicemailDefaultTypeTest (1)
VoiceMailIconSelectableTest (5)
VoicemailSettingsFromMessageModeScreenTest (2)
VoicemailSettingsTest (7)

上面保留了您的输入顺序并且几乎没有在内存中存储任何内容，它不关心您的输入是否已排序，它只依赖于您的输入文件中连续出现的所有重复键，就像您在示例中显示的那样。

于 2017-10-31T18:58:24.510 回答
0

使用 bash 数组

unset tab
declare -A tab
while read line;do
  let tab["$line"]=${tab["$line"]}+1
done < infile
for i in ${!tab[*]} ;do
  echo "$i  (${tab[$i]})"
done | sort
于 2017-10-31T23:45:32.537 回答
0

无需awk根据第一次出现保持键的顺序，并且不需要排序或分组输入。

cat -n file    |     # add line numbers for order
sort -k2       |     # sort based on keys, ignoring line no
uniq -f1 -c    |     # count keys, ignoring line no
sort -k2,2n    |     # sort by line no to recover initial order
sed -r 's/(\S+)\s+(\S+)\s+(\S+)/\3 (\1)/'     # format output
于 2017-10-31T19:36:44.980 回答