6

我打开了很多 PDF，我想在解析完 PDF 后删除它们，但文件在程序完成运行之前保持打开状态。如何关闭使用 PyPDF2 打开的 PDf？

代码：

def getPDFContent(path):
    content = ""
    # Load PDF into pyPDF
    pdf = PyPDF2.PdfFileReader(file(path, "rb"))

    #Check for number of pages, prevents out of bounds errors
    max = 0
    if pdf.numPages > 3:
        max = 3
    else:
        max = (pdf.numPages - 1)

    # Iterate pages
    for i in range(0, max): 
        # Extract text from page and add to content
        content += pdf.getPage(i).extractText() + "\n"
    # Collapse whitespace
    content = " ".join(content.replace(u"\xa0", " ").strip().split())
    #pdf.close()
    return content
4

3 回答 3

7

只需自己打开和关闭文件

f = open(path, "rb")
pdf = PyPDF2.PdfFileReader(f)
f.close()

PyPDF2.read()是您传入的流，就在构造函数中。所以在初始对象构造之后，你可以只折腾文件。

上下文管理器也可以工作：

with open(path, "rb") as f:
    pdf = PyPDF2.PdfFileReader(f)
do_other_stuff_with_pdf(pdf)
于 2017-10-30T17:47:51.483 回答
2

这样做时：

pdf = PyPDF2.PdfFileReader(file(path, "rb"))

您正在传递对句柄的引用，但您无法控制文件何时关闭。

您应该使用句柄创建一个上下文，而不是从这里匿名传递它：

我会写

with open(path,"rb") as f:

    pdf = PyPDF2.PdfFileReader(f)
    #Check for number of pages, prevents out of bounds errors
    ... do your processing
    # Collapse whitespace
    content = " ".join(content.replace(u"\xa0", " ").strip().split())
# now the file is closed by exiting the block, you can delete it
os.remove(path)
# and return the contents
return content
于 2017-10-30T17:45:45.273 回答
2

是的，您正在将流传递给 PdfFileReader，您可以将其关闭。with语法更适合为您执行此操作：

def getPDFContent(path):
    with open(path, "rb") as f:
        content = ""
        # Load PDF into pyPDF
        pdf = PyPDF2.PdfFileReader(f)

        #Check for number of pages, prevents out of bounds errors
        max = 0
        if pdf.numPages > 3:
            max = 3
        else:
            max = (pdf.numPages - 1)

        # Iterate pages
        for i in range(0, max): 
            # Extract text from page and add to content
            content += pdf.getPage(i).extractText() + "\n"
        # Collapse whitespace
        content = " ".join(content.replace(u"\xa0", " ").strip().split())
        return content
于 2017-10-30T17:47:18.510 回答