3

我的代码有一个Subjectwhich，当添加新值时会触发一个 HTTP 请求，该请求返回一个Observable.

我想以两种不同的方式处理这些数据（使用相同的数据），并将结果Observables存储在group和作为使用管道times放入的值。ngForasync

虽然这确实有效，但 HTTP 请求会发送多次 - 我只希望每个订阅发送一次。

下面是一个最小的例子。

import { Component, OnInit } from "@angular/core";
import { Observable } from "rxjs/Observable";
import { Subject } from "rxjs/Subject";

import { ExampleService } from "../example.service";

import "rxjs/add/operator/switchMap";

@Component({
  templateUrl: "./example.component.html",
  styleUrls: ["./example.component.scss"]
})
export class ExampleComponent implements OnInit {

  constructor(
    private exampleService: ExampleService
  ) { }

  ngOnInit() {

    var selections = new Subject<string>();

    var appointments = selections
      // exampleService.getData returns an HTTP observable.
      .switchMap(date => this.exampleService.getData(date));

    var group = appointments
      .map(data => this.process(data));

    var times = appointments
      .map(data => this.calculateTimes(data));

    // Calling subscribe each time sends the HTTP request multiple
    // times - I only want it to be send once for both of them: they
    // can share the data!!
    group.subscribe();
    times.subscribe();

    // selections.next(someData) is called periodically from some
    // omitted code.
  }

  processExample(data: string[]) {
    /*
     * Some processing code.
    */

    return data;
  }

  calculateTimes(data: string[]) {
    /*
     * Some processing code.
    */

    return data;
  }
}

实现这一目标的最佳方法是什么？

4

1 回答 1

5

您可以使用share运算符来归档您要查找的内容：

import 'rxjs/add/operator/share';

ngOnInit() {

  var selections = new Subject<string>();

  var appointments = selections
    // exampleService.getData returns an HTTP observable.
    .switchMap(date => this.exampleService.getData(date))
    .share();

  var group = appointments
    .map(data => this.process(data));

  var times = appointments
    .map(data => this.calculateTimes(data));

  // Calling subscribe each time sends the HTTP request multiple
  // times - I only want it to be send once for both of them: they
  // can share the data!!
  group.subscribe();
  times.subscribe();

  // selections.next(someData) is called periodically from some
  // omitted code.
}

基本上，不同的observers共享source它们之间的相同。

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于 2017-10-26T22:04:29.887 回答