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我有一个查询，它将对 6 个表执行连接并根据条件获取各种列。我想添加一个额外的过滤条件，它只会给我那些拥有count(distinct dateCaptured)>30. 我可以使用Group byand获取满足此条件的成员列表having。但由于这一情况，我不想按其他列名分组。我需要PARTITION BY在这种情况下使用。

样品表a

+-----+------------+--------------+
| Id  | Identifier | DateCaptured |
+-----+------------+--------------+
| 1   |      05548 | 2017-09-01   |
| 2   |      05548 | 2017-09-01   |
| 3   |      05548 | 2017-09-01   |
| 4   |      05548 | 2017-09-02   |
| 5   |      05548 | 2017-09-03   |
| 6   |      05548 | 2017-09-04   |
| 7   |      37348 | 2017-08-15   |
| 8   |      37348 | 2017-08-15   |
| .   |            |              |
| .   |            |              |
| .   |            |              |
| 54  |      37348 | 2017-10-15   |
+-----+------------+--------------+

询问

SELECT  a.value,
        b.value, c.value,
        d.value
        FROM Table a
    INNER JOIN Table b on a.Id=b.id
    INNER JOIN Table c on a.Id=c.Id and s.Invalid=0
    INNER JOIN Table d on a.Id=d.Id

假设表 a 有 30 多条 Identifier 记录37348。我怎样才能只获得上述查询的这个标识符。

这些是我对上述 SELECT 感兴趣的患者。

SELECT  a.Identifier,count(DISTINCT DateCaptured)
    FROM Table a
    INNER JOIN Table b on a.Id=b.id
    INNER JOIN Table c on a.Id=c.Id and s.Invalid=0
    INNER JOIN Table d on a.Id=d.Id 
    GROUP BY Identifier
    HAVING count(DISTINCT DateCaptured)>30
4

3 回答 3

1 
WITH cte as (
    SELECT  a.Identifier
    FROM Table a
    INNER JOIN Table b on a.Id=b.id
    INNER JOIN Table c on a.Id=c.Id and s.Invalid=0
    INNER JOIN Table d on a.Id=d.Id 
    GROUP BY Identifier
    HAVING count(DISTINCT DateCaptured) > 30
)
SELECT  a.value,
        b.value, c.value,
        d.value
FROM Table a
INNER JOIN Table b on a.Id=b.id
INNER JOIN Table c on a.Id=c.Id and s.Invalid=0
INNER JOIN Table d on a.Id=d.Id 
INNER JOIN cte on cte.Identifier = a.Identifier
于 2017-10-24T20:57:24.543 回答
1 
SELECT  a.value,
        b.value, c.value,
        d.value
        FROM Table a
    INNER JOIN Table b on a.Id=b.id
    INNER JOIN Table c on a.Id=c.Id and s.Invalid=0
    INNER JOIN Table d on a.Id=d.Id 
WHERE a.Identifier IN (SELECT  a1.Identifier  
    FROM Table a1
    GROUP BY a1.Identifier HAVING count(DISTINCT a1.DateCaptured)>30)
于 2017-10-24T21:01:33.763 回答
1

如果多行确实在tableA，那么你可以这样做：

SELECT a.value, b.value, c.value, d.value
FROM (SELECT a.*, COUNT(*) OVER (PARTITION BY id) as cnt
      FROM a
     ) a INNER JOIN
     b 
     ON a.Id = b.id INNER JOIN 
     c 
     ON a.Id = c.Id AND s.Invalid = 0 INNER JOIN 
     d 
     ON a.Id = d.Id
WHERE a.cnt > 30;

注意：如果您仍然需要count(distinct)，您可以执行以下操作：

SELECT a.value, b.value, c.value, d.value
FROM (SELECT a.*, SUM(CASE WHEN seqnum = 1 THEN 1 ELSE 0 END) OVER (PARTITION BY id) as cnt
      FROM (SELECT a.*, ROW_NUMBER() OVER (PARTITION BY id ORDER BY DateCaptured) as seqnum
            FROM a
           ) a
     ) a INNER JOIN
     b 
     ON a.Id = b.id INNER JOIN 
     c 
     ON a.Id = c.Id AND s.Invalid = 0 INNER JOIN 
     d 
     ON a.Id = d.Id
WHERE a.cnt > 30;
于 2017-10-24T21:19:32.927 回答