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当我将 URL 硬编码为 ReadJSON().execute(my url here);

但是,将 url 更改为 textinput 后​​,它将不会加载图像。

这是预期的结果:https ://imgur.com/a/QyKG1

这是整个文件:https ://pastebin.com/e6Q5ViuS

这是包含错误的代码:

class ReadJSON extends AsyncTask<String, Integer, String> {

        @Override
        protected String doInBackground(String... params) {
            return readURL(params[0]);
        }

        @Override
        protected void onPostExecute(String content) {
            try {

                JSONArray jsonArray = new JSONArray(content);

                for(int i =0;i<jsonArray.length(); i++){
                    JSONObject productObject = jsonArray.getJSONObject(i);
                    arrayList.add(new Product(
                            productObject.getString("photo"),
                            productObject.getString("author")

                    ));
                }
            } catch (JSONException e) {
                e.printStackTrace();
            }
            CustomListAdapter adapter = new CustomListAdapter(
                    getApplicationContext(), R.layout.custom_list_layout, arrayList
            );
            lv.setAdapter(adapter);
        }
    }


    private static String readURL(String theUrl) {
        StringBuilder content = new StringBuilder();
        try {
            // create a url object
            URL url = new URL(theUrl);
            // create a urlconnection object
            URLConnection urlConnection = url.openConnection();
            // wrap the urlconnection in a bufferedreader
            BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()));
            String line;
            // read from the urlconnection via the bufferedreader
            while ((line = bufferedReader.readLine()) != null) {
                content.append(line + "\n");
            }
            bufferedReader.close();
        } catch (Exception e) {
            e.printStackTrace();
        }
        return content.toString();
    }
}
4

1 回答 1

0

问题在这里:

txtUrl.getText().toString();

您没有初始化txtUrl,这意味着 Android 不知道它txtUrl是什么。您可以将其更改为:

txtUrl = (EditText) findViewById(R.id.youredittextid);
EditTextValue = txtUrl.getText().toString();
于 2017-10-22T18:40:02.877 回答