django - Django：ModelMultipleChoiceField 不会保存数据

Question

我的模型表单有一个带有 ModelMultipleChoiceField 的字段，该字段有一个 Category 对象的查询集。问题是表单提交，但类别数据没有保存。想法？

非常感谢！

形式：

class MealForm(forms.ModelForm):
  class Meta:
    model = Meal
    fields = ('category','date','time')

  category = forms.ModelMultipleChoiceField(
        label=_("Food style"),
        queryset=Category.objects.all(),
                                  required=True)

看法

@login_required
def new_meal(request, template_name="meal/newmeal.html"):

  if request.method == 'POST':
    form = MealForm(request.POST)
    form.mom = request.user
    if form.is_valid():
      meal = form.save(commit=False)
      meal.mom = request.user
      meal.save()
      return HttpResponseRedirect('/meal/%d' % meal.id )
  else:
    form = MealForm()

  data = {
    'form': form,
    'add': True
  }

楷模：

class Category(models.Model):

  name = models.CharField(default='',max_length=100)
  num_tags = models.IntegerField(default=0)

  def __unicode__(self):
          return "%s" % self.name
  class Meta:
    ordering = ['name']

class Meal(models.Model):
  category = models.ManyToManyField(Category)

Answer 1

你需要在你做的时候使用，mymodelform.save_m2m()因为没有 ID（又名）就无法保存 m2m 关系。commit=FalseModelFormsave(commit=True)

如果没有先保存父模型，则中间表 (m2m) 没有要引用的 ID！

http://docs.djangoproject.com/en/dev/topics/forms/modelforms/#the-save-method

@login_required
def new_meal(request, template_name="meal/newmeal.html"):

  if request.method == 'POST':
    form = MealForm(request.POST)
    form.mom = request.user
    if form.is_valid():
      meal = form.save(commit=False)
      meal.mom = request.user
      meal.save()
      form.save_m2m() # save m2m after meal has id

      return HttpResponseRedirect('/meal/%d' % meal.id )
  else:
    form = MealForm()

  data = {
    'form': form,
    'add': True
  }