c# - 将 App.xaml 设置为 UserControl WPF（以连接定位器）

Question

情况 ：

我目前正在尝试将 my 连接DataContext到我的ViewModel. 我正在使用GalaSoftMvvmLight.

但事实是我没有.Window因为我将把这段代码集成到另一个程序中，该程序有Window. 所以我只有UserControl.

问题 ：

我不知道为什么，但我无法连接我DataContext的UserControl.

我收到这个错误{"Cannot find resource named 'Locator'. Resource names are case sensitive."}

问题 ：

如何将我的 App.xaml 资源正确连接到我的 View ？如果没有它是不可能的Window，我怎么能用这样DataContext的东西打电话

<UserControl.DataContext>
    SOMETHING TO SET DATACONTEXT WITH BINDING !
</UserControl.DataContext>

这是我的代码：

应用程序.xaml

<Application x:Class="SOMETHING.App" xmlns:vm="clr-namespace:SOMETHING.ViewModel" StartupUri="ApplicationView.xaml">
    <Application.Resources>
        <ResourceDictionary>
            <vm:ViewModelLocator x:Key="Locator" />
        </ResourceDictionary>
    </Application.Resources>
</Application>

应用程序视图.xaml

<UserControl x:Class="SOMETHING.View.ApplicationView"
         <!-- THIS ONE DOESN'T WORK -->
         DataContext="{Binding ApplicationVM, Source={StaticResource Locator}}">

    <!-- THIS ONE DOESN'T WORK IF I SET <vm:ViewModelLocator x:Key="Locator" /> IN STYLE.XAML, BUT I CAN'T USE IT IN USERCONTROL PARAMETERS (LIKE ABOVE) -->
    <UserControl.Resources>
        <ResourceDictionary >
            <ResourceDictionary.MergedDictionaries >
                <ResourceDictionary Source="Style.xaml"/>
            </ResourceDictionary.MergedDictionaries>
        </ResourceDictionary>
    </UserControl.Resources>

    <Grid>
         <Label Content="{Binding Title}" />
    </Grid>
</UserControl>

视图模型定位器

public class ViewModelLocator
{
    public ViewModelLocator()
    {
        ServiceLocator.SetLocatorProvider(() => SimpleIoc.Default);

        if (ViewModelBase.IsInDesignModeStatic)
        {
            SimpleIoc.Default.Register<IDataService, Design.DesignDataService>();
        }
        else
        {
            SimpleIoc.Default.Register<IDataService, DataService>();
        }

        SimpleIoc.Default.Register<ApplicationViewModel>();
    }

    public ApplicationViewModel ApplicationVM
    {
        get { return SimpleIoc.Default.GetInstance<ApplicationViewModel>();
    }
}

Answer 1

如果ViewModelLocator类和类UserControl位于同一个项目/程序集中，您可以在合并到这样ViewModelLocator的 a 中定义资源：ResourceDictionaryUserControl

<UserControl ...>
    <UserControl.Resources>
        <ResourceDictionary>
            <ResourceDictionary.MergedDictionaries>
                <ResourceDictionary Source="Global.xaml" />
            </ResourceDictionary.MergedDictionaries>
        </ResourceDictionary>
    </UserControl.Resources>
    <UserControl.DataContext>
        <Binding Path="ApplicationVM" Source="{StaticResource Locator}" />
    </UserControl.DataContext>
    <Grid>

    </Grid>
</UserControl>

全局.xaml：

<ResourceDictionary xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
                    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
                    xmlns:local="clr-namespace:WpfControlLibrary1">
    <local:ViewModelLocator x:Key="Locator" />
</ResourceDictionary>