java - 我正在做一个抛硬币游戏程序。但是我在这部分有一个错误 [ (if Guess==i) {. 我该如何解决这个问题？

Question

import java.util.Scanner;

public class CoinTossGame {
public static void main(String[] args) {


   System.out.println("A coin is tossed!");

      int Heads=0, Tails=1;

   Scanner input = new Scanner (System.in);

   System.out.println("Enter your guess.");   //Starting message
   System.out.println("Press 0 for Heads and 1 for Tails.");   //prompts user to enter the input

        String Guess = input.nextLine( );   //Stored input in variable
        int i= (int) (Math.random () * 2);   //Store random number

        if (Guess==i) {
        System.out.println("Nice guess.\nYou are really guenius!!"); 
    }
        else {
        System.out.println("Opps! wrong guess.");
        System.out.println("Try again.");
        System.out.println("Thank you.");
   }

}
}

Answer 1

您将整数与字符串进行比较。那显然行不通。转换Guess成int或i转换成String.

Answer 2

您正在将 aint与 a进行比较String：if (Guess==i)

你需要的是 2 个整数：

int guess = Integer.parseInt(input.nextLine());    //or  int guess = input.nextInt();
int i = (int) (Math.random () * 2);                //Store random number

if (guess==i) {
    System.out.println("Nice guess.\nYou are really guenius!!"); 
}

---

或与 2 Strings：

String guess = input.nextLine();    
String i = ((int) (Math.random () * 2)) + "";

if (guess.equals(i)) {                      // for object use equals() and not ==
    System.out.println("Nice guess.\nYou are really guenius!!"); 
}