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这是查看哪个 url 可以安全浏览的代码。我已经使用了 google api。我面临的问题是我无法让 SafeBrowsing 类对象访问给定的 url。所以请看看是否有人有解决方案。

 public static void main(final String[] args) {
    try {
        final String baseURL = "https://safebrowsing.googleapis.com/v4/threatMatches:find?key=xxx";
        final URL url = new URL(baseURL);

        // Get a URLConnection object, to write to POST method
        final HttpURLConnection connect = (HttpURLConnection) url.openConnection();
        connect.setRequestMethod("POST");
        connect.setRequestProperty("Content-Type", "application/json");
        // Specify connection settings
        connect.setDoInput(true);
        connect.setDoOutput(true);
        final ClientInfo clientInfo = new Ggooggle().getClientInfo();
        final ThreatInfo threatInfo = new Ggooggle().getThreatInfo();
        final FindThreatMatchesRequest request = new FindThreatMatchesRequest();
        request.setClient(clientInfo);
        request.setThreatInfo(threatInfo);
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1 回答 1

1

尝试这个。

public final NetHttpTransport httpTransport = GoogleNetHttpTransport.newTrustedTransport();
public static final JacksonFactory GOOGLE_JSON_FACTORY = JacksonFactory.getDefaultInstance();

Safebrowsing.Builder safebrowsingBuilder = new Safebrowsing.Builder(httpTransport, GOOGLE_JSON_FACTORY, null);
Safebrowsing safebrowsing = safebrowsingBuilder.build();
FindThreatMatchesResponse findThreatMatchesResponse = safebrowsing.threatMatches().find(findThreatMatchesRequest).setKey(GOOGLE_API_KEY).execute();

List<ThreatMatch> threatMatches = findThreatMatchesResponse.getMatches();

if (threatMatches != null && threatMatches.size() > 0) {
    for (ThreatMatch threatMatch : threatMatches) {
        threatUrls.add(threatMatch.getThreat().getUrl());
    }
}

完整示例代码：https ://github.com/kalinchih/java_google_safebrowsing_v4

于 2018-02-28T13:52:26.220 回答