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如何确定多边形中一个点的经纬度?

<Polygon>
<extrude>0</extrude>
<tessellate>1</tessellate>
<altitudeMode>clampToGround</altitudeMode>
<outerBoundaryIs>
<LinearRing>
<coordinates>-88.346745,30.390702,0.0 -88.346823,30.389936,0.0 -88.345543,30.389914,0.0 -88.344316,30.389981,0.0 -88.342645,30.390004,0.0 -88.340765,30.390161,0.0 -88.335731,30.388969,0.0 -88.33412,30.388741,0.0 -88.33289,30.389146,0.0 -88.333095,30.389878,0.0 -88.335702,30.389727,0.0 -88.340504,30.391513,0.0 -88.341235,30.391738,0.0 -88.342384,30.391468,0.0 -88.343507,30.391445,0.0 -88.345047,30.3914,0.0 -88.346745,30.390702,0.0</coordinates>
</LinearRing>
</outerBoundaryIs>
</Polygon>`
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1 回答 1

0

使用 Java API for KML (JAK),您可以解析 KML 文件,然后提取其坐标。

下面是一段 Java 代码,用于从 KML 文件中提取坐标。

JAXBContext jc = JAXBContext.newInstance(Kml.class);

// create KML reader to parse arbitrary KML into Java Object structure
Unmarshaller u = jc.createUnmarshaller();
Kml kml = (Kml) u.unmarshal(new File("test.kml"));

Placemark placemark = (Placemark) kml.getFeature();
Polygon geom = (Polygon) placemark.getGeometry();
LinearRing linearRing = geom.getOuterBoundaryIs().getLinearRing();
List<Coordinate> coordinates = linearRing.getCoordinates();
for (Coordinate coordinate : coordinates) {
    System.out.println(coordinate.getLongitude());
    System.out.println(coordinate.getLatitude());
    System.out.println(coordinate.getAltitude());
}
于 2017-09-21T21:49:38.790 回答