即使我将设置“严格”设置为 false,laravel 5.5 group by 在单个列上也不起作用。我已经尝试了 mysql 工作台中的原始查询,它工作正常,但我在 laravel 上遇到此错误:
SQLSTATE[42000]: Syntax error or access violation: 1055 'hammer.vehicle.consignor_id' isn't in GROUP BY (SQL: select `vehicle`.*, `vehicle_brand`.`vehicle_brand_name`, `vehicle_model`.`vehicle_model_name`, `vehicle_variant`.`vehicle_variant_name`, `vehicle_model`.`year`, `vehicle`.`vehicle_id` from `vehicle` left join `vehicle_brand` on `vehicle_brand`.`vehicle_brand_id` = `vehicle`.`vehicle_brand_id` left join `vehicle_model` on `vehicle_model`.`vehicle_brand_id` = `vehicle_brand`.`vehicle_brand_id` left join `vehicle_variant` on `vehicle_variant`.`vehicle_model_id` = `vehicle_model`.`vehicle_model_id` group by `vehicle`.`vehicle_id` limit 10 offset 0)
这是导致错误的laravel代码
\DB::table('vehicle')
->select('vehicle.*', 'vehicle_brand.vehicle_brand_name', 'vehicle_model.vehicle_model_name', 'vehicle_variant.vehicle_variant_name', 'vehicle_model.year', 'vehicle.vehicle_id')
->leftJoin('vehicle_brand', 'vehicle_brand.vehicle_brand_id', '=', 'vehicle.vehicle_brand_id')
->leftJoin('vehicle_model', 'vehicle_model.vehicle_brand_id', '=', 'vehicle_brand.vehicle_brand_id')
->leftJoin('vehicle_variant', 'vehicle_variant.vehicle_model_id', '=', 'vehicle_model.vehicle_model_id')
->where($where)
->groupBy('vehicle.vehicle_id')
->paginate(10);
配置“严格”中的 mysql 设置已设置为 false