select SUM(value)
from /measurment1|measurment2/
where time > now() - 60m and host = 'hostname' limit 2;
名称:测量1
time sum
---- ---
1505749307008583382 4680247
名称:测量2
time sum
---- ---
1505749307008583382 3004489
但是是否有可能获得 SUM(measurment1+measurment2) 的值,所以我只看到 o/p 。