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import ctypes
import struct
class _sPOS(ctypes.Structure):
_fileds_ = (
    ("POSX", ctypes.c_double),
    ("POSY", ctypes.c_double)
)
sPOS = _sPOS()
class _sPOSE(ctypes.Structure):
_fileds_ = (
    ("sPOSX", sPOS),
    ("sPOSY", sPOS),
    ("sDirection", ctypes.c_double)
)
with open('/Users/machcross/Desktop/MasterDB_03M17D15H34m54s.dat','wb') as f:
sPOSE = _sPOSE()
sPOSE.sPOSX = 0.1
sPOSE.sPOSY = 0.2
sPOSE.sDirection = 0.01
size = ctypes.sizeof(sPOSE)
print(size)
  1. 如何获取 sPOS 的大小?len(sPOS) 不起作用.. ctypes.sizeof(sPOS) 为零..

  2. 我想知道如何制作 bytearray(sPOS) 因为.. ex) buf = ((char*)&_sPOS,sizeof(sPOS))

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