matplotlib - 带有图例的 Matplotlib 维恩图

Question

我正在使用 matplotlib-venn 包在 python 中绘制维恩图。这个包非常适合用两到三组绘制维恩图。但是，当其中一组比其他组大得多时，较小圆圈中的计数可能会接近或重叠。这是一个例子。

from collections import Counter
import matplotlib.pyplot as plt
from matplotlib_venn import venn2, venn3

sets = Counter()
sets['01'] = 3000
sets['11'] = 3
sets['10']  = 5
setLabels = ['set1', 'set2']

plt.figure()
ax = plt.gca()
v = venn2(subsets = sets, set_labels = setLabels, ax = ax)
plt.title('Venn Diagram')
plt.show()

我要做的是将计数（在本例中为 3000、3 和 5）移动到颜色与图中颜色匹配的图例中。不确定如何使用 matplotlib_venn 执行此操作。

Answer 1

您可以用空字符串替换维恩图的标签，而是从维恩的补丁和相应的计数创建一个图例，如下所示：

from collections import Counter
import matplotlib.pyplot as plt
from matplotlib_venn import venn2, venn3

sets = Counter()
sets['01'] = 3000
sets['11'] = 3
sets['10']  = 5
setLabels = ['set1', 'set2']

plt.figure()
ax = plt.gca()
v = venn2(subsets = sets, set_labels = setLabels, ax = ax)

h, l = [],[]
for i in sets:
    # remove label by setting them to empty string:
    v.get_label_by_id(i).set_text("")
    # append patch to handles list
    h.append(v.get_patch_by_id(i))
    # append count to labels list
    l.append(sets[i])

#create legend from handles and labels    
ax.legend(handles=h, labels=l, title="counts")

plt.title('Venn Diagram')
plt.show()