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(s/def ::users (s/coll-of ::user :distinct true))

上面的规范要求每个用户映射是不同的,但我如何指定它来:user/ids仅检查不同的

不应允许以下集合:

[{:id 10 :name "Jessica"} {:id 10 :name "Erica"}]
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1 回答 1

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(s/def ::id (s/int-in 0 40)) ; just for testing purposes
(s/def ::name string?)
(s/def ::user (s/and (s/keys :req-un [::id ::name])))
(s/def ::user-list (s/and
                       (s/coll-of ::user :distinct true :into [])
                       #(if (empty? %) true (apply distinct? (mapv :id %)))))

(deftest so-test
    (let [users [{:id 11 :name "Jessica"} {:id 11 :name "Erica"}]]
        (prn (g/generate (s/gen ::user-list)))
        (s/assert ::user-list users)))
于 2017-09-10T01:58:08.547 回答