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我尝试编写一个代码，加密我的数据，然后我尝试执行我的代码我得到一个错误：

import base64
import boto3
from Crypto.Cipher import AES

PAD = lambda s: s + (32 - len(s) % 32) * ' '


def get_arn(aws_data):
    return 'arn:aws:kms:{region}:{account_number}:key/{key_id}'.format(**aws_data)


def encrypt_data(aws_data, plaintext_message):
    kms_client = boto3.client(
        'kms',
        region_name=aws_data['region'])

    data_key = kms_client.generate_data_key(
        KeyId=aws_data['key_id'],
        KeySpec='AES_256')

    cipher_text_blob = data_key.get('CiphertextBlob')
    plaintext_key = data_key.get('Plaintext')

    # Note, does not use IV or specify mode... for demo purposes only.
    cypher = AES.new(plaintext_key, AES.MODE_EAX)
    encrypted_data = base64.b64encode(cypher.encrypt(PAD(plaintext_message)))

    # Need to preserve both of these data elements
    return encrypted_data, cipher_text_blob



def main():
    # Add your account number / region / KMS Key ID here.
    aws_data = {
        'region': 'eu-west-1',
        'account_number': '70117777xxxx',
        'key_id': 'xxxxxxx-83ac-4b5e-93d4-xxxxxxxx',
    }

    # And your super secret message to envelope encrypt...
    plaintext = b'Hello, World!'

    # Store encrypted_data & cipher_text_blob in your persistent storage. You will need them both later.
    encrypted_data, cipher_text_blob = encrypt_data(aws_data, plaintext)
    print(encrypted_data)


if __name__ == '__main__':
    main()

这是一个错误：

PAD = lambda s: s + (32 - len(s) % 32) * ' ' TypeError: can't concat str to bytes 也许谁知道问题出在哪里？请建议

4

1 回答 1

1

您的函数PAD旨在使用输入，并使用输入（在您的示例中）string调用它。bytesb'Hello, World!'

PAD('Hello, World!')（没有前导b）有效。一种解决方案是将明文填充为 astring并将其转换为bytes之后，例如：

plaintext = PAD('Hello, world!') plaintext_bytes = plaintext.encode('utf-8')

请参阅此 StackOverflow 问题，了解如何将 a 转换string为bytes.

于 2017-09-05T09:03:28.267 回答