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我想在 WPF 的设计窗口中显示虚拟数据GridView并找到了一个类似的示例:答案:xaml 中数据模板的设计时间数据 - 代码日志

我创建了一个新的 WPF 应用程序 (.NET Framework 4.6.1) WpfDataTemplate,在示例代码片段中命名并复制MainWindow.xaml.csMainWindow.xaml. 所有添加都在注释中注明##

意外行为:

  1. 该行<local:MyMockClass x:Key="DesignViewModel" />产生错误“对象引用未设置为对象的实例”。

  2. 字符串不会显示test text #在 Designer 中。

  3. 运行时字符串不会显示test text #在窗口中。

问题:

  1. 错误的原因是什么?

  2. 我需要更改哪些代码才能按预期工作?


主窗口.xaml

<Window x:Class="WpfDataTemplate.MainWindow"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
    xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
    xmlns:local="clr-namespace:WpfDataTemplate"
    mc:Ignorable="d"
    Title="MainWindow" Height="350" Width="525">
<!-- ## BEGIN ADD -->
<Window.Resources>
    <local:MyMockClass x:Key="DesignViewModel" />
</Window.Resources>
<!-- ## END ADD -->
<Grid>
    <!-- ## BEGIN ADD -->
    <ListBox x:Name="standardLayoutListBox" 
             d:DataContext="{Binding Source={StaticResource DesignViewModel}}"
             ItemsSource="{Binding MyListBoxItems}">
        <ListBox.ItemTemplate>
            <DataTemplate>
                <Grid>
                    <Grid.RowDefinitions>
                        <RowDefinition />
                        <RowDefinition />
                    </Grid.RowDefinitions>
                    <Label Grid.Column="0" Content="{Binding text1}" />
                    <Label Grid.Column="1" Content="{Binding text2}" />
                </Grid>
            </DataTemplate>
        </ListBox.ItemTemplate>
    </ListBox>
    <!-- ## END ADD -->
</Grid>

主窗口.xaml.cs

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
// ## BEGIN ADD
using System.Collections.ObjectModel; 
// ## END ADD

namespace WpfDataTemplate
{
    // ## BEGIN ADD
    public class MyMockClass
    {
        public MyMockClass()
        {
            MyListBoxItems.Add(new MyDataClass() { text1 = "test text 1", text2 = "test text 2" });
            MyListBoxItems.Add(new MyDataClass() { text1 = "test text 3", text2 = "test text 4" });
        }
        public ObservableCollection<MyDataClass> MyListBoxItems { get; set; }
    }

    public class MyDataClass
    {
        public string text1 { get; set; }
        public string text2 { get; set; }
    }
    // ## END ADD

    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();
        }
    }
}
4

1 回答 1

2

首先,您需要在MyMockClass.

public class MyMockClass
{
    public MyMockClass()
    {
        MyListBoxItems = new ObservableCollection<MyDataClass>()
        MyListBoxItems.Add(new MyDataClass() { text1 = "test text 1", text2 = "test text 2" });
        MyListBoxItems.Add(new MyDataClass() { text1 = "test text 3", text2 = "test text 4" });
    }
    public ObservableCollection<MyDataClass> MyListBoxItems { get; set; }
}

我在我的窗口中使用设计实例,如下所示:

d:DataContext="{d:DesignInstance Type=local:MyMockClass, IsDesignTimeCreatable=True}"
于 2017-09-01T09:41:29.283 回答