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I'm using an Excel dataset where the time values, MM:SS, come in numeric values that I need to convert to POSIXct in r and then make calculations.

Below is sample data of what I have and I need to get

dfOrig <- data.frame(StandarTime =  c(615,735,615 ),
                 AchievedTime =  c(794,423,544 ))

This is what I'm looking for:

dfCleaned <- data.frame(StandarTime =  c("2017-08-25 10:15",
                                     "2017-08-25 12:15",
                                     "2017-08-25 10:15" ),
                    AchievedTime =  c("2017-08-25 13:14 PDT",
                                      "2017-08-25 7:03 PDT",
                                      "2017-08-25 9:04 PDT" ))

I'm not sure how to best approach this problem.

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1 回答 1

3

不确定这些值是什么，但如果这些是您可以使用的秒数：

> dfOrig$StandarTime <- ISOdate(2017, 8, 25, hour = 0) + dfOrig$StandarTime
> dfOrig$AchievedTime <- ISOdate(2017, 8, 25, hour = 0) + dfOrig$AchievedTime
> dfOrig
          StandarTime        AchievedTime
1 2017-08-25 00:10:15 2017-08-25 00:13:14
2 2017-08-25 00:12:15 2017-08-25 00:07:03
3 2017-08-25 00:10:15 2017-08-25 00:09:04

ISOdate(2017, 8, 25, hour = 0)设置开始时间，然后您可以添加一个以秒为单位的值。您还可以使用指定时区tz = ""

于 2017-08-25T19:26:19.347 回答