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我正在尝试在 Visual Studio 2008 中创建 Web 服务调用。但是在运行 android 应用程序时,我在模拟器中没有得到任何输出。你能告诉我我的编码中有什么问题,以便我可以解决它。

_

Public Function HelloWorld() As String 
Return "Hello how are you"
End Function

同样在android的.java文件中,我使用的编码为:

package com.webservicetest;
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import android.app.Activity;


public class webservicetest extends Activity {
private static final String NAMESPACE = "http://localhost/webservicetest/" ;
private static final String URL = "http://192.168.1.10/webservicetest/Service.asmx";
private static final String HelloWorld_SOAP_ACTION = "http://localhost/webservicetest/HelloWorld";
private static final String METHOD_NAME1 = "HelloWorld";

public static void main(String[] args)
{
GetHelloWorld();
}
/** Called when the activity is first created. */
public static void GetHelloWorld() {

SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME1);
//SoapSerializationEnvelope envelope =new SoapSerializationEnvelope(SoapEnvelope.VER11);


SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);

HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
try
{

androidHttpTransport.call(HelloWorld_SOAP_ACTION, envelope);
SoapObject response = (SoapObject)envelope.getResponse();
int result = Integer.parseInt(response.getProperty(0).toString());




}
catch(Exception e)
{   
e.printStackTrace();

}

}
}

我收到错误,int result = Integer.parseInt(response.getProperty(0).toString());因为“永远不会读取局部变量结果”。

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1 回答 1

0

您指出的错误并不是使您的应用程序无法运行的原因,它仅表示您正在使用变量但从未读取过它。在 Android 开发中,您不使用main()方法,但大多数情况下您会覆盖Activity.onCreate().

在这里你可以找到一些教程。

GetHelloWorld()方法似乎还可以)

于 2011-01-03T22:17:35.530 回答