2

我目前有一个包含几个字符串的列表视图。这些是从 strings.xml 中的字符串数组调用的

<string name="app_name">Taxi Me</string>
<string-array name="taxi_array">
    <item>Barrys Taxi</item>
    <item>Boom Taxi</item>

</string-array>

我试图做的是为这些创建子项，以便我可以显示地址和联系方式等字段。我不久前做了一个customlistview，但无法弄清楚如何使用strings.xml文件来做到这一点？我需要使用任何特定标签以便它们显示在列表视图中吗？

主要活动代码：

    public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    final String[] taxi = getResources().getStringArray(R.array.taxi_array);
    final String[] address = getResources().getStringArray(R.array.taxi_add);

    setListAdapter(new ArrayAdapter<String>(this, R.layout.listtaxi, taxi));

    final ListView lv = getListView();
    lv.setTextFilterEnabled(true);

    for (int i = 0; i < taxi.length; i++) {
        lv.add(new ListTaxi (taxi[i], address[i]));
    }

 /*lv.setOnItemClickListener(new OnItemClickListener() {
      public void onItemClick(AdapterView<?> parent, View view,
          int position, long id) {
        // When clicked, show a toast with the TextView text
        Toast.makeText(getApplicationContext(), ((TextView) view).getText(),
            Toast.LENGTH_LONG).show();
      }
    });
   */
        lv.setOnItemClickListener(new OnItemClickListener() {
        public void onItemClick(AdapterView<?> a, View v, final int position, long id)
       {   
            final int selectedPosition = position;
            AlertDialog.Builder adb=new AlertDialog.Builder(ListTaxi.this); 
             adb.setTitle("Taxi Booking");
             adb.setMessage("You Have Selected: "+lv.getItemAtPosition(position)); 
             adb.setPositiveButton("Book", new DialogInterface.OnClickListener() {
                 public void onClick(DialogInterface dialog, int id) {
                     Intent intent = new Intent(getApplicationContext(), Booking.class);
                     intent.putExtra("booking",  taxi[selectedPosition]);
                     startActivity(intent);
                 }
             });
             adb.setNegativeButton("Cancel", null); 
             adb.show(); 
         }
     });
4

3 回答 3

7

编辑：好的，只是为了好玩，我把它放在一起。它可以正确编译和运行，看看您是否可以根据您的特定需求对其进行调整：

布局/taxi_list_item.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="100dp"
    android:padding="10dp"
    android:orientation="vertical"
    >
    <TextView
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:id="@+id/taxi_name"
        />
    <TextView
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:id="@+id/taxi_address"
        />
</LinearLayout>

布局/main.xml

<?xml version="1.0" encoding="utf-8"?>
<ListView
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:id="@+android:id/list"
    android:layout_width="match_parent" 
    android:layout_height="match_parent" 
    />

TaxiMain.java

package com.test.taxi;

import java.util.ArrayList;
import java.util.List;

import android.app.ListActivity;
import android.content.Context;
import android.os.Bundle;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.TextView;

public class TaxiMain extends ListActivity {
    /** Called when the activity is first created. 
     * @return */

    class Taxi {
        private String taxiName;
        private String taxiAddress;

        public String getName() {
            return taxiName;
        }

        public void setName(String name) {
            taxiName = name;
        }

        public String getAddress() {
            return taxiAddress;
        }

        public void setAddress(String address) {
            taxiAddress = address;
        }

        public Taxi(String name, String address) {
            taxiName = name;
            taxiAddress = address;
        }
    }

    public class TaxiAdapter extends ArrayAdapter<Taxi> {
        private ArrayList<Taxi> items;
        private TaxiViewHolder taxiHolder;

        private class TaxiViewHolder {
            TextView name;
            TextView address; 
        }

        public TaxiAdapter(Context context, int tvResId, ArrayList<Taxi> items) {
            super(context, tvResId, items);
            this.items = items;
        }

        @Override
        public View getView(int pos, View convertView, ViewGroup parent) {
            View v = convertView;
            if (v == null) {
                LayoutInflater vi = (LayoutInflater)getSystemService(LAYOUT_INFLATER_SERVICE);
                v = vi.inflate(R.layout.feed_view, null);
                taxiHolder = new TaxiViewHolder();
                taxiHolder.name = (TextView)v.findViewById(R.id.taxi_name);
                taxiHolder.address = (TextView)v.findViewById(R.id.taxi_address);
                v.setTag(taxiHolder);
            } else taxiHolder = (TaxiViewHolder)v.getTag(); 

            Taxi taxi = items.get(pos);

            if (taxi != null) {
                taxiHolder.name.setText(taxi.getName());
                taxiHolder.address.setText(taxi.getAddress());
            }

            return v;
        }
    }

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        String[] taxiNames = getResources().getStringArray(R.array.taxi_name_array);
        String[] taxiAddresses = getResources().getStringArray(R.array.taxi_address_array);

        ArrayList<Taxi> taxiList = new ArrayList<Taxi>();

        for (int i = 0; i < taxiNames.length; i++) {
            taxiList.add(new Taxi(taxiNames[i], taxiAddresses[i]));
        }

        setListAdapter(new TaxiAdapter(this, R.layout.taxi_list_item, taxiList));      
    }
}

_ __ _ _END 编辑_ _ __ _ __

你可能会更好地使用数据库来做这样的事情，将记录捆绑在一起。如果您打算使用数组，您可以做的一件事是为您需要的每个项目创建一个单独的数组（例如，taxi_array、taxi_address_array、taxi_phone_array），然后在您的代码中创建一个 Taxi 对象：

class Taxi {
    String taxiName;
    String taxiAddress;
    String taxiPhone;

    public Taxi(String name, String address, String phone) {
        taxiName = name;
        taxiAddress = address;
        taxiPhone = phone;
    }
}

private List<Taxi> taxiList;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    String[] taxiNames = getResources().getStringArray("taxi_array");
    String[] taxiAddresses = getResources().getStringArray("taxi_address_array");
    String[] taxiPhones = getResources().getStringArray("taxi_phone_array");
    taxiList = new ArrayList<Taxi>();

    for (int i = 0; i < taxiNames.length; i++) {
        taxiList.add(new Taxi(taxiNames[i], taxiAddresses[i], taxiPhones[i]));
    }
}

（这是未编译的代码，可能需要进行一些调整）但是您将拥有一个出租车项目列表，其中包含来自不同数组的所有已编译信息。数据库仍然是一个更好的选择（甚至是包含数据的 CSV 文件，在您的资产中）。

于 2011-01-03T19:36:15.157 回答
3

我有同样的问题，我这样解决了自己：你可以像这样简单地添加子项，你不需要这么多的编码！

    <string name="app_name">Taxi Me</string>
    <string-array name="taxi_array">
<item>
     <item>Barrys Taxi</item>
     <item>adress</item>
     <item>contact</item>
     <item>ANY THING...</item>
</item>

<item>
     <item>Boom Taxi</item>
     <item>adress</item>
     <item>contact</item>
     <item>ANY THING...</item>
</item>
    </string-array>
于 2013-11-11T19:11:51.333 回答
0

Are you looking for some sort of nested Lists?
Have a look at ExpandableListView:
http://developer.android.com/reference/android/widget/ExpandableListView.html
and
http://mylifewithandroid.blogspot.com/2008/05/expandable-lists.html

于 2011-01-03T19:20:04.780 回答