0

这个查询为我们提供了各种操作的时间。现在它按名称、日期和铲子模型分解每个事件的时间。但是，我希望以某种方式将一个工作人员中所有名字的平均值加入一个新列。作为 SQL 游戏的新手，如果有一种策略可以提供各种平均定义并将它们返回到同一个表中，那就太好了。输出图片遵循此链接。

https://i.stack.imgur.com/6V5XB.png

DECLARE @start AS DATETIME = '2017-08-15'

DECLARE @end AS DATETIME = '2017-08-20'

SELECT *

FROM ( 

SELECT 

[Name],
[Date],
MAX([Crew]) as [Crew],
MAX([Shovel_ID]) as [Shovel Model],
CONVERT(DECIMAL(10,1) ,AVG([empty])) as [Empty],
CONVERT(DECIMAL(10,1) ,AVG([HAUL])) AS [Hauling],
CONVERT(DECIMAL(10,0) ,AVG([Wait At Dump]*60)) AS [Wait at Dump],
CONVERT(DECIMAL(10,0) ,AVG([Dumping]*60)) as [Dumping],
CONVERT(DECIMAL(10,0) ,AVG([Spot at LU]*60)) as [Spot at LU],
CONVERT(DECIMAL(10,0) ,AVG([Load Time]*60)) AS [Truck Loading],
CONVERT(DECIMAL(10,0) ,AVG([QUEUE]*60)) as [Wait at Shovel],
CONVERT(DECIMAL(10,0) ,AVG([Hot Seat]*60)) as [Hot Seat],
CONVERT(DECIMAL(10,0) ,AVG([Empty Hauling]*60)) as [Empty Stopped],
CONVERT(DECIMAL(10,0) ,AVG([HAULING STOPPED]*60)) AS [Hauling Stopped]


FROM (

Select  
haul_cycle,
max([name]) as [Name],
max([shovel_id]) as [Shovel_ID],
max([date]) as [Date], 
max([crew]) as [Crew],
sum(dumping) as [Dumping],
sum([spot at lu]) as [Spot at LU],
sum([wait at dump]) as [Wait at Dump],
sum([empty]) as [Empty],
sum([hauling]) as [Haul],
SUM([Truck Loading]) as [Load Time],
SUM([Queue at LU]) as [QUEUE],
SUM([Hot Change]) as [Hot Seat],
SUM([EMPTY sTOPPED]) AS [Empty Hauling],
SUM([HAULing STOPPED]) AS [Hauling Stopped],

SUM([HAULing STOPPED]+[EMPTY STOPPED]+[Queue at LU]+[Truck Loading]+
[Hauling]+[Empty]+[Spot at LU]+[wait at dump]+[dumping]) as [Cycle Time],
COUNT([HAUL_CYCLE]) AS [Number of Cycles]

FROM (

SELECT 
HAUL_CYCLE_TRANS.HAUL_CYCLE_REC_IDENT as [HAUL_CYCLE],
CREW_IDENT as [CREW],
badge.LAST_NAME + ' , '  + badge.FIRST_NAME as [Name],
DUMP_END_SHIFT_DATE as date ,
DUMP_END_SHIFT_IDENT,
CAST(EQUIPMENT_STATUS_TRANS.END_TIMESTAMP-
EQUIPMENT_STATUS_TRANS.START_TIMESTAMP AS FLOAT)*24*60 AS DURATION,
COALESCE(SUB_STATUS_DESC, STATUS_DESC) AS [Status],

CASE 
    WHEN HAUL_CYCLE_TRANS.LOADING_UNIT_IDENT IN (4001, 4002, 4005, 4006) 
THEN '6060'
    ELSE '7495'
END AS SHOVEL_ID  

FROM HAUL_CYCLE_TRANS

LEFT JOIN HAUL_UNIT_STATUS_TRANS_COL on 
HAUL_UNIT_STATUS_TRANS_COL.HAUL_CYCLE_REC_IDENT = 
HAUL_CYCLE_TRANS.HAUL_CYCLE_REC_IDENT

LEFT JOIN EQUIPMENT_STATUS_TRANS on 
EQUIPMENT_STATUS_TRANS.EQUIP_STATUS_REC_IDENT = 
HAUL_UNIT_STATUS_TRANS_COL.EQUIP_STATUS_REC_IDENT

LEFT JOIN badge on badge.BADGE_IDENT = 
haul_cycle_trans.HAULING_UNIT_BADGE_IDENT

LEFT JOIN EQUIP_STATUS_CODE on EQUIP_STATUS_CODE.STATUS_CODE = 
EQUIPMENT_STATUS_TRANS.STATUS_CODE


LEFT JOIN EQUIP_SUB_STATUS_CODE on EQUIP_SUB_STATUS_CODE.SUB_STATUS_CODE = 
EQUIPMENT_STATUS_TRANS.SUB_STATUS_CODE

WHERE dump_end_shift_date >= @start AND First_Name <> '') raw_data 

PIVOT(SUM(duration) FOR [Status] IN ([Dumping], [Spot at LU],[Wait at Dump], 
[Empty], [Empty Stopped], [Hauling Stopped], [Hauling], [Queue at LU], 
[Truck Loading], [Hot Change])) DATAFIELD

GROUP BY haul_cycle) SUM_DATA_FOR_EACH_REC
GROUP BY [name], [date], Shovel_ID
) AVG_OPERATOR_STATUS

ORDER BY [NAME],[DATE]
4

1 回答 1

0

您可以使用该OVER (PARTITION BY)功能。

这样，您可以通过以不同的方式对数据集进行分区，从而使用您希望平均值具有的任何拆分。

您可以在此处阅读有关OVER条款的更多信息。

例子：

SELECT
    DateField
    ,YourName1
    ,YourId
    ,SUM(Value1)
    ,AVG(Value1) OVER (PARTITION BY DateField) AS DateFieldAverage
FROM
    YourTable
GROUP BY
    DateField
    ,YourName1
    ,YourId

假设您使用的是 SQL Server（基于您问题之上的语法）。

于 2017-08-22T11:47:31.903 回答