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我必须向工作同事提供一些数据，并且在 MySQL 中分析它时遇到问题。

我有一张名为“付款”的桌子。每笔付款都有以下列：

  1. 客户（我们的客户，例如银行）
  2. Amount_gbp（交易价值的英镑等值）
  3. 货币
  4. 原产国
  5. Client_type（个人或公司）

我写了非常简单的查询，例如：

SELECT  
    AVG(amount_GBP), 
    COUNT(client) AS '#Of Results'
FROM payments

WHERE client_type = 'individual'
    AND amount_gbp IS NOT NULL
    AND currency = 'TRY'
    AND country_origin = 'GB'
    AND date_time BETWEEN '2017/1/1' AND '2017/9/1'

但我真正需要做的是从平均值中消除异常值和/或只包括与平均值有一定标准偏差的结果。

例如，忽略 2% 的结果中的前/后 10 个结果等。和/或忽略平均值中 2 个 STDEV 之外的任何结果

任何人都可以帮忙吗？

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1 回答 1

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--- 编辑后的答案 -- 尝试让我知道 ---

最好的办法是使用 avg 和 std_dev 值创建一个 TEMPORARY 表并与它们进行比较。让我知道这是否不可行：

CREATE TEMPORARY TABLE payment_stats AS
 SELECT
  AVG(p.amount_gbp) as avg_gbp,
  STDDEV(amount_gbp) as std_gbp,
  (SELECT MIN(srt.amount_gbp) as max_gbp
    FROM (SELECT amount_gbp
     FROM payments
     <... repeat where no p. ...>
     ORDER BY amount_gbp DESC
     LIMIT <top_numbers to ignore>
   ) srt
  ) max_g,
  (SELECT MAX(srt.amount_gbp) as min_gbp
    FROM (SELECT amount_gbp
     FROM payments
     <... repeat where no p. ...>
     ORDER BY amount_gbp ASC
     LIMIT <top_numbers to ignore>
   ) srt
  ) min_g
 FROM payments
 WHERE client_type = 'individual'
  AND amount_gbp IS NOT NULL
  AND currency = 'TRY'
  AND country_origin = 'GB'
  AND date_time BETWEEN '2017/1/1' AND '2017/9/1';

然后，您可以与临时表进行比较

SELECT  
 AVG(p.amount_gbp) as avg_gbp, 
 COUNT(p.client) AS '#Of Results'
FROM payments p
WHERE
 p.amount_gbp >= (SELECT (avg_gbp - std_gbp*2) 
                FROM payment_stats)
 AND p.amount_gbp <= (SELECT (avg_gbp + std_gbp*2) 
                FROM payment_stats)
 AND p.amount_gbp > (SELECT min_g FROM payment_stats)
 AND p.amount_gbp < (SELECT max_g FROM payment_stats)
 AND p.client_type = 'individual'
 AND p.amount_gbp IS NOT NULL
 AND p.currency = 'TRY'
 AND p.country_origin = 'GB'
 AND p.date_time BETWEEN '2017/1/1' AND '2017/9/1';

- 稍后的

DROP TEMPORARY TABLE payment_stats;

请注意，我必须重复 WHERE 条件。也可以更改为您需要*2的任何内容！<factor>

还是呸！

每次比较都会检查不同的统计数据

让我知道这是否更好

于 2017-08-21T20:32:04.943 回答