9

当我在 tinymce 中添加图像时,这是我得到的默认 html 源代码:

<p><img class="img-responsive img-post" src="/Images/uploads/img.png" alt="" /></p>

我该如何改变这个?类似于:

<p><img class="img-responsive img-post" data-original="/Images/uploads/img.png" src="/Images/loading.gif" alt="" /></p>

在我有原始数据作为 src 并且 src 是加载图标的地方,它需要像这样,因为我对图像进行了延迟加载。

我知道您可以使用以下方法扩展有效元素:

extend_valid_elements: "data-original"

但是如何更改默认 html 源代码的结构?是否有类似选择确定图像插入回调的东西?

更新:

这是我的tinymce启动代码:

/******************************tinyMce*******************************/
function tinyMce() {
    tinymce.init({
        theme: "modern",
        selector: "#mceEditor",
        height: 500,
        extend_valid_elements: "data-original",
        relative_urls: true,
        convert_urls: false,
        image_advtab: true,
        image_title: false,
        image_description: false,
        image_dimensions: false,
        image_class_list: [
            { title: "Responsive", value: "lazy img-responsive img-post" }
        ],
        image_list: function (success) {
            $.ajax({
                url: "/Image/List",
                type: "GET",
                dataType: "json",
                success: function (data) {
                    success(data);
                }
            });
        },
        // enable automatic uploads of images represented by blob or data URIs
        automatic_uploads: true,
        // URL of our upload handler (for more details check: https://www.tinymce.com/docs/configure/file-image-upload/#images_upload_url)
        images_upload_url: "/Image/Upload",
        // here we add custom filepicker only to Image dialog
        file_picker_types: "image",
        // and here's our custom image picker
        file_picker_callback: function (cb, value, meta) {
            var input = document.createElement("input");
            input.setAttribute("type", "file");
            input.setAttribute("accept", "image/*");

            // Note: In modern browsers input[type="file"] is functional without 
            // even adding it to the DOM, but that might not be the case in some older
            // or quirky browsers like IE, so you might want to add it to the DOM
            // just in case, and visually hide it. And do not forget do remove it
            // once you do not need it anymore.

            input.onchange = function () {
                var file = this.files[0];

                var reader = new FileReader();
                reader.readAsDataURL(file);
                reader.onload = function () {
                    // Note: Now we need to register the blob in TinyMCEs image blob
                    // registry. In the next release this part hopefully won't be
                    // necessary, as we are looking to handle it internally.
                    var id = "blobid" + (new Date()).getTime();
                    var blobCache = tinymce.activeEditor.editorUpload.blobCache;
                    var base64 = reader.result.split(',')[1];
                    var blobInfo = blobCache.create(id, file, base64);
                    blobCache.add(blobInfo);

                    // call the callback and populate the Title field with the file name
                    cb(blobInfo.blobUri(), { title: file.name });
                };
            };

            input.click();
        }
    });
}

我现在正在考虑另一种方式,如果我可以将tinymce中的默认src属性替换为data-original,那将是完美的,但是在tinymce内部,如果我使用data-original,它不会显示图片,它只是显示空白. 有没有办法在添加图像时告诉tinymce,放置data-original而不是src并从data-original而不是src读取?

所以从这里:

<p><img class="img-responsive img-post" src="/Images/uploads/img.png" alt="" /></p>

对此根本没有 src:

<p><img class="img-responsive img-post" data-original="/Images/uploads/img.png" alt="" /></p>
4

3 回答 3

4

这是一种检测图像何时插入编辑器的方法。

JS

var newSrc = "/Images/loading.gif";


tinymce.init({
  selector: 'textarea',
  plugins: "image",
  toolbar: "image",
  height: 350,
    setup: function(editor){
    editor.on('NodeChange', function (e) {
      if(e.element.tagName === "IMG"){          
        e.element.setAttribute("data-original", e.element.currentSrc);
        e.element.setAttribute("src", newSrc);
      }
    });
  }
});

NodeChange您可以通过监听事件来访问元素。然后检查tagName是类型IMG。然后我们就正常设置我们的属性。

检查这个演示

于 2017-08-17T17:23:03.167 回答
2

...但是在tinymce内部,如果我使用原始数据,它不会显示图片,它只会显示空白。

继续做你正在做的事情,只需添加一个更改处理程序来添加新的 src...

editor.on('Change', function (e) {
    // Get images that have data-original attribute but not src
    $( 'img[data-original]' ).not( 'img[src]' )
      .attr( 'src', '/Images/loading.gif' ) // Add src
} );
于 2017-09-05T04:56:50.937 回答
2

您可以使用正则表达式和字符串替换方法解决此问题, 该函数将返回匹配项的替换。如下例所示

// tinymce returning string
let content = '<p><img class="img-responsive img-post" src="/Images/uploads/img.png" alt="" /></p><p><img class="img-responsive img-post" src="/Images/uploads/img2.png" alt="" /></p>';

// searching through all the img tags in the content..
content = content.replace(/<img(\s+[^>]*)src="([^"]*)"([^>]*)>/g,function(full,key, value){
 return `<img ${key} src="/Images/loading.gif" data-original="${value}" alt="">`;
});


//content replaced
console.log(content);

一个正则表达式用于匹配所有的img标签,然后我们只是新的data-original属性并将其替换为原始字符串

于 2017-09-05T12:54:59.330 回答