3

出于研究目的，我需要构建一组良性程序。首先，我需要从http://downloads.informer.com获取这些程序。为此，我编写了一个 Python 脚本，它迭代每个下载页面并将下载链接提取到一个列表中。之后，脚本使用这些链接下载程序（这些程序是 exe、msi 或 zip 文件）。不幸的是，在这一步，脚本遇到错误，指出（AttributeError：'Request' object has no attribute 'decode'）。

以下是在单页上工作并检索单个程序的脚本（为简单起见）：

import wget
from urllib.request import urlopen as uReq
from bs4 import BeautifulSoup as soup
my_url = 'http://sweet-home-3d.informer.com/download'

import urllib.request
req = urllib.request.Request(
    my_url, 
    data=None, 
    headers={
        'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_9_3) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.47 Safari/537.36'
    }
)


uClient = uReq(req)
page_html = uClient.read()

page_soup = soup(page_html, 'lxml' )

cont01 = page_soup.findAll('a', {'class':'download_button'})

conts = cont01[1]
ref= conts['href']

addr = urllib.request.Request(
    ref, 
    data=None, 
    headers={
        'User-Agent': 'Mozilla/5.0'
    }
)
wget.download(addr)

我得到的错误如下：

AttributeError                            Traceback (most recent call last)
<ipython-input-1-93c4caaa1777> in <module>()
     31     }
     32 )
---> 33 wget.download(addr)

C:\Users\bander\Anaconda3\lib\site-packages\wget.py in download(url, out, bar)
    503 
    504     # get filename for temp file in current directory
--> 505     prefix = detect_filename(url, out)
    506     (fd, tmpfile) = tempfile.mkstemp(".tmp", prefix=prefix, dir=".")
    507     os.close(fd)

C:\Users\bander\Anaconda3\lib\site-packages\wget.py in detect_filename(url, out, headers, default)
    482         names["out"] = out or ''
    483     if url:
--> 484         names["url"] = filename_from_url(url) or ''
    485     if headers:
    486         names["headers"] = filename_from_headers(headers) or ''

C:\Users\bander\Anaconda3\lib\site-packages\wget.py in filename_from_url(url)
    228     """:return: detected filename as unicode or None"""
    229     # [ ] test urlparse behavior with unicode url
--> 230     fname = os.path.basename(urlparse.urlparse(url).path)
    231     if len(fname.strip(" \n\t.")) == 0:
    232         return None

C:\Users\bander\Anaconda3\lib\urllib\parse.py in urlparse(url, scheme, allow_fragments)
    292     Note that we don't break the components up in smaller bits
    293     (e.g. netloc is a single string) and we don't expand % escapes."""
--> 294     url, scheme, _coerce_result = _coerce_args(url, scheme)
    295     splitresult = urlsplit(url, scheme, allow_fragments)
    296     scheme, netloc, url, query, fragment = splitresult

C:\Users\bander\Anaconda3\lib\urllib\parse.py in _coerce_args(*args)
    112     if str_input:
    113         return args + (_noop,)
--> 114     return _decode_args(args) + (_encode_result,)
    115 
    116 # Result objects are more helpful than simple tuples

C:\Users\bander\Anaconda3\lib\urllib\parse.py in _decode_args(args, encoding, errors)
     96 def _decode_args(args, encoding=_implicit_encoding,
     97                        errors=_implicit_errors):
---> 98     return tuple(x.decode(encoding, errors) if x else '' for x in args)
     99 
    100 def _coerce_args(*args):

C:\Users\bander\Anaconda3\lib\urllib\parse.py in <genexpr>(.0)
     96 def _decode_args(args, encoding=_implicit_encoding,
     97                        errors=_implicit_errors):
---> 98     return tuple(x.decode(encoding, errors) if x else '' for x in args)
     99 
    100 def _coerce_args(*args):

AttributeError: 'Request' object has no attribute 'decode'

如果有人能帮我解决这个问题，我将不胜感激。预先感谢。

4

2 回答 2

2

Wget 给出 HTTP 错误 503：使用正确的 URL 直接调用时服务暂时不可用。我猜它在服务器上被阻止了。下载链接由 JavaScript 生成。您可以使用硒。这将执行 JavaScript 以获取 URL。我用 PhantomJS 尝试了 Selenium，但它没有用。但是对于 Chrome，它确实如此。

首先安装硒：

sudo pip3 install selenium

然后获取驱动程序https://sites.google.com/a/chromium.org/chromedriver/downloads 并将其放在您的路径中。如果（与我不同）您在 Windows 或 Mac 上，则可以使用无头版本的 chrome“Chrome Canary”。

from selenium import webdriver
from time import sleep

url = 'http://sweet-home-3d.informer.com/download'
browser = webdriver.Chrome()
browser.get(url)
browser.find_element_by_class_name("download_btn").click()
sleep(360) # give it plenty of time to download this will depend on you internet connection
browser.quit()

该文件将下载到您的下载文件夹。如果它退出得太快，您将获得带有额外文件扩展名 .crdownload 的文件的一部分。如果发生这种情况，请增加您传递给睡眠的值。

于 2017-08-12T12:19:58.843 回答
1

实际上，您不需要 Selenium。这是一个cookie问题。我相信你也可以用 urllib 以某种方式做 cookie，但这不是我的专业领域。

如果您要在请求中完成这项工作 - 没有浏览器和 wget - 您可以像这样获取文件：

import requests
from bs4 import BeautifulSoup as bs

# you need headers or the site won't let you grab the data
headers = {

  "user-agent": "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_4) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/62.0.3181.0 Safari/537.36"
}
url = 'http://sweet-home-3d.informer.com/download/'

# you need a cookie to download. Create a persistens session
s = requests.Session()
r = s.get(url, headers=headers)
soup = bs(r.text, "html.parser")

# all download options lie in a div with class table
links_table = soup.find('div', {'class': 'table'})
file_name = links_table.find('div', {'class': 'table-cell file_name'})['title']
download_link = links_table.find('a', {'class': 'download_button'})['href']

# for some reason the url-page doesn't set the cookie you need.
# the subpages do, so we need to get it from one of them - before we call download_link

cookie_link = links_table.a['href']
r = s.get(cookie_link, headers=headers)

# now with a cookie set, we can download the file
r = s.get(download_link,headers=headers)
with open(file_name, 'wb') as f:
    f.write(r.content)
于 2017-08-12T22:34:22.167 回答