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我知道 describe 命令\dselect count(*) from my_schema_1.my_table_1;. 但是,我想获得整个数据库的整洁列表,我有很多表。像下面这样的东西会很好。

my_schema_1   | mytable_1   | 12323
my_schema_2   | mytable_2   | 0

我基本上想遍历所有表格。

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1 回答 1

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可能是这样的(无需为每个表执行 COUNT(*)):

编辑新版本以考虑没有预测的表格:

SELECT
    t.table_schema AS schema,
    t.table_name AS table,
    ZEROIFNULL(
        CASE WHEN p.is_segmented IS TRUE 
            THEN SUM(ps.row_count) * COUNT(DISTINCT ps.node_name) // COUNT(ps.node_name) 
            ELSE MAX(ps.row_count)
        END
    ) AS row_count,
    CASE WHEN p.is_segmented THEN 'Yes' ELSE 'No' END AS segmented,
    COUNT(DISTINCT p.projection_id) AS num_proj
FROM
    v_catalog.tables t
    LEFT OUTER JOIN v_monitor.projection_storage ps
        ON t.table_id = ps.anchor_table_id 
    LEFT OUTER JOIN v_catalog.projections p
        ON t.table_id = p.anchor_table_id
        AND p.is_super_projection IS TRUE
GROUP BY
    t.table_schema, t.table_name, p.is_segmented
ORDER BY
    t.table_schema, t.table_name
;

样本输出:

 schema |         table          | row_count | segmented | num_proj 
--------+------------------------+-----------+-----------+----------
 mauro  | city                   |         5 | Yes       |        2
 mauro  | employees              |   1000000 | Yes       |        2
 mauro  | empty                  |         0 | No        |        0
 mauro  | fnames                 |        20 | Yes       |        2
 ...
 tpch   | customer               |         0 | Yes       |        2
 tpch   | lineitem               |  54010935 | Yes       |        2
 tpch   | nation                 |        25 | No        |        1
 tpch   | orders                 | 718277000 | Yes       |        2

我确实添加了几列:(segmented是/否)和num_proj。如果需要,您可以删除它们。

于 2017-08-11T12:28:56.520 回答