我有一个正则表达式列表,并希望返回这些行,其中包含一个通过任何正则表达式的字段。反正有类似以下的东西:
SELECT * FROM Foo as f WHERE f.bar IN ("regex1","regex2");
在 EJBQL 中似乎根本不可能使用正则表达式,所以我猜我必须使用本机(MySQL)查询。
Why not combine the regexes into one?
"(?:" + regex1 + ")|(?:" + regex2 + ")"
So if regex1 = "^.*foo(.*)bar"
and regex2 = "baz(.*)frob$"
, you'd get
(?:^.*foo(.*)bar)|(?:baz(.*)frob$)
No, this is not possible. At least not the way you think it is.
Do this instead: Insert the regexes as rows into a table. Then query
SELECT
*
FROM
Foo AS f
INNER JOIN Regexes AS re ON f.bar REGEXP re.pattern