我有一个矩阵，我想计算第i行和每隔一行之间的距离（比如说欧几里得）（即我想要成对距离矩阵的第i行）。
#include <Rcpp.h>
#include <cmath>
#include <algorithm>
#include <RcppParallel.h>
//#include <RcppArmadillo.h>
#include <queue>
using namespace std;
using namespace Rcpp;
using namespace RcppParallel;
// [[Rcpp::export]]
double dist_fun(NumericVector row1, NumericVector row2){
double rval = 0;
for (int i = 0; i < row1.length(); i++){
rval += (row1[i] - row2[i]) * (row1[i] - row2[i]);
}
return rval;
}
// [[Rcpp::export]]
NumericVector dist_row(NumericMatrix mat, int i){
NumericVector row(mat.nrow());
NumericMatrix::Row row1 = mat.row(i - 1);
for (int j = 0; j < mat.nrow(); j++){
NumericMatrix::Row row2 = mat.row(j);
row(j) = dist_fun(row1, row2);
}
return row;
}
// [[Rcpp::depends(RcppParallel)]]
struct JsDistance: public Worker {
// input matrix to read from
const NumericMatrix mat;
int i;
// output vector to write to
NumericVector output;
// initialize from Rcpp input and output matrixes (the RMatrix class
// can be automatically converted to from the Rcpp matrix type)
JsDistance(const NumericMatrix mat, int i, NumericVector output)
: mat(mat), i(i), output(output) {}
// function call operator that work for the specified range (begin/end)
void operator()(std::size_t begin, std::size_t end) {
NumericVector row1 = mat.row(i);
for (std::size_t j = begin; j < end; j++) {
NumericVector row2 = mat.row(j);
output[j] = dist_fun(row1, row2);
}
}
};
// [[Rcpp::export]]
NumericVector parallel_dist_row(NumericMatrix mat, int i) {
// allocate the matrix we will return
NumericVector output(mat.nrow());
// create the worker
JsDistance JsDistance(mat, i, output);
// call it with parallelFor
parallelFor(0, mat.nrow(), JsDistance);
return output;
}
使用 Rcpp 的顺序方式是上面写的函数“row_dist”。然而我想使用的矩阵非常大，所以我想并行化它。但是后来我会遇到一个我不太明白为什么的段错误。要触发错误，您可以运行以下代码：
library(Rcpp)
library(RcppParallel)
setThreadOptions(numThreads = 20)
set.seed(42)
X = matrix(rnorm(10000 * 400), 10000, 400)
sourceCpp("question.cpp")
start1 = proc.time()
print(dist_row(X, 2)[1:30])
print(proc.time() - start1)
start2 = proc.time()
print(parallel_dist_row(X, 2)[1:30])
print(proc.time() - start2)
有人可以给我一些关于我做错了什么的提示吗？在此先感谢您的时间！
==================================================== ======================
编辑：
inline double d(double a, double b){
return fabs(a - b);
}
// [[Rcpp::depends(RcppParallel)]
struct dtwDistance: public Worker {
// Input matrix to read from must be of the RMatrix<T> form
// if using Rcpp objects
const RMatrix<double> mat;
int i;
// Output vector to write to must be of the RVector<T> form
// if using Rcpp objects
RVector<double> output;
// initialize from Rcpp input and output matrixes (the RMatrix class
// can be automatically converted to from the Rcpp matrix type)
dtwDistance(const NumericMatrix mat, int i, NumericVector output)
: mat(mat), i(i - 1), output(output) {}
// Note the -1 ^^^^ to match results from prior function
// Function call operator to iterate over a specified range (begin/end)
void operator()(std::size_t begin, std::size_t end) {
RMatrix<double>::Row row1 = mat.row(i);
for (std::size_t j = begin; j < end; ++j) {
RMatrix<double>::Row row2 = mat.row(j);
size_t n = row1.length();
size_t m = row2.length();
NumericMatrix cost(n + 1, m + 1);
for (int ii = 1; ii <= n; ii++){
cost(i, 0) = numeric_limits<double>::infinity();
}
for (int jj = 1; jj <= m; jj++){
cost(0, j) = numeric_limits<double>::infinity();
}
for (int ii = 1; ii <= n; ii++){
for (int jj = 1; jj <= m; jj++){
double dist = d(row1[ii - 1], row2[jj - 1]);
cost(ii, jj) = dist + min(min(cost(ii - 1, jj), cost(ii, jj - 1)), cost(ii - 1, jj - 1));
//cout << ii << ", " << jj << ", " << cost(ii, jj) << "\n";
}
}
output[j] = cost(n, m);
}
}
};
// [[Rcpp::export]]
NumericVector parallel_dist_row_dtw(NumericMatrix mat, int i) {
// allocate the matrix we will return
//RMatrix<double> input(mat);
NumericVector y(mat.nrow());
//RVector<double> output(y);
// create the worker
dtwDistance dtwDistance(mat, i, y);
// call it with parallelFor
parallelFor(0, mat.nrow(), dtwDistance);
return y;
}
我需要计算的距离是动态时间扭曲距离。我如上所述实现了它。然而在运行时，它会给出一个“堆栈不平衡”的警告。并且运行几次后会出现段错误。我想知道现在有什么问题。
为了触发这个问题，我做了：
library(Rcpp)
library(RcppParallel)
setThreadOptions(numThreads = 4)
sourceCpp("scripts/chisq_dtw.cpp")
set.seed(42)
X = matrix(rnorm(1000), 100, 10)
parallel_dist_row_dtw(X, 1)
parallel_dist_row_dtw(X, 2)
parallel_dist_row_dtw(X, 3)
parallel_dist_row_dtw(X, 4)
parallel_dist_row_dtw(X, 5)