3

我有一个包含人员 FormArray 的表单。people 数组然后包含地址的 FormArray，它给了我以下 JSON：

{
  "people": [
    {
      "lastName": "Last-1",
      "firstName": "First-1",
      "middleName": "",
      "addresses": [
        {
          "street": "Person1 - Address1"
        },
        {
          "street": "Person1 - Address2"
        }
      ]
    },
    {
      "lastName": "Last-2",
      "firstName": "Last-2",
      "middleName": "",
      "addresses": [
        {
          "street": "Person2 - Address1"
        }
      ]
    }
  ]
}

现在我正在尝试从表单中获取这些“人”并创建一个 Person 对象数组

export class ReportPerson {    
    lastName: string = '';
    firstName: string = '';
    middleName: string = ''; 
    addresses: PersonAddress[];
}
export class PersonAddress {
        street: string = '';   
}

当我使用 console.log(form.get('people').value); 我得到以下结果：

(2) [{…}, {…}]0: {lastName: "Last-1", firstName: "First-1", middleName: "", 
addresses: Array(2)}
              1: {lastName: "Last-2", firstName: "Last-2", middleName: "", 
addresses: Array(1)}length: 2__proto__: Array(0)

但是无论我如何尝试获取数据，它都说我的列表是未定义的。例如，以下返回它无法读取未定义的“lastName”。

 save(form: any) {
        var reportPersonList: ReportPerson[] = new Array();
        var people = form.get('people');

        for (let i = 0; i < people.length; i++) {
            console.log(people[i].lastName);
       }
    }
}

我的问题是，从 FormArray 中的数据创建人员对象数组的正确语法是什么？我知道这是我缺少的一些基本内容，但我已经习惯了 C# 并且对 Typescript/Angular2 很陌生。

4

2 回答 2

2

对于遇到此问题的其他人，我可以通过从“人员”表单数组的值创建一个新表单数组来解决它。然后使用表单数组函数将表单值映射到对象值。然后我对地址数组重复了这个过程。

save(form: any) {
    var reportPersonList: ReportPerson[] = new Array();

    var people = form.get('people') as FormArray;

    for (let i = 0; i < people.length; i++) {
        var p = new ReportPerson;
        p.lastName = people.at(i).get('lastName').value;
        p.firstName = people.at(i).get('firstName').value;
        p.middleName = people.at(i).get('middleName').value;
        var addresses = people.at(i).get('addresses') as FormArray;
        for (let j = 0; j < addresses.length; j++) {
            var a = new PersonAddress;
            a.street = addresses.at(j).get('street').value;

            p.addresses.push(a);
        };
        reportPersonList.push(p);
    }
    this.reportFormDataService.setReportPeople(reportPersonList);

}
于 2017-08-14T02:12:20.823 回答
1

很高兴你让它工作了！

以为我会发布我会如何做到这一点。

let json = {
  "people": [
    {
      "lastName": "Last-1",
      "firstName": "First-1",
      "middleName": "",
      "addresses": [
        {
          "street": "Person1 - Address1"
        },
        {
          "street": "Person1 - Address2"
        }
      ]
    },
    {
      "lastName": "Last-2",
      "firstName": "Last-2",
      "middleName": "",
      "addresses": [
        {
          "street": "Person2 - Address1"
        }
      ]
    }
  ]
}

// for each person in the array, return a class instantiate
json.people.map(person => {
  return new Person().deserialize(person);
});

// 
class Person(){

  public lastName: string;
  public middleName: string;
  public firstName: string;
  public addresses: Array<any>

  constructor(){
    this.addresses = new Array<string>();
  }

  // note you could of just used the constructor,
  // but its a personal preference to have a serialize and deserialize for data coming from the server in a json object type.
  deserialize(data: any){
    this.lastName = data.lastName;
    this.firstName = data.firstName;
    this.middleName = data.middleName;
    this.addresses = data.addresses;
  }
}
于 2017-08-14T02:26:48.583 回答