我得到了这样的图像(它是一个图表):
(来源:kitconet.com)
我想改变颜色,所以白色是黑色,图形线是浅蓝色等。GD和PHP可以实现吗?
这将用灰色替换白色
$imgname = "test.gif";
$im = imagecreatefromgif ($imgname);
$index = imagecolorclosest ( $im, 255,255,255 ); // get White COlor
imagecolorset($im,$index,92,92,92); // SET NEW COLOR
$imgname = "result.gif";
imagegif($im, $imgname ); // save image as gif
imagedestroy($im);
我无法使这个解决方案发挥作用。图像不能是真彩色图像。首先用 imagetruecolortopalette() 转换它;
$imgname = "test.gif";
$im = imagecreatefromgif ($imgname);
imagetruecolortopalette($im,false, 255);
$index = imagecolorclosest ( $im, 255,255,255 ); // get White COlor
imagecolorset($im,$index,92,92,92); // SET NEW COLOR
$imgname = "result.gif";
imagegif($im, $imgname ); // save image as gif
imagedestroy($im);
我知道这已经很晚了,但我已经编写了一个脚本,可以在更大的范围内执行此操作。希望看到这篇文章的人可以使用它。它需要许多单色层的源图像(您的选择)。您为其提供源颜色和每一层的色调,脚本返回一个合成图像(具有完全透明度),专门为您提供的十六进制代码着色。
查看下面的代码。更详细的解释可以在我的博客上找到。
function hexLighter($hex, $factor = 30) {
$new_hex = '';
$base['R'] = hexdec($hex{0}.$hex{1});
$base['G'] = hexdec($hex{2}.$hex{3});
$base['B'] = hexdec($hex{4}.$hex{5});
foreach ($base as $k => $v) {
$amount = 255 - $v;
$amount = $amount / 100;
$amount = round($amount * $factor);
$new_decimal = $v + $amount;
$new_hex_component = dechex($new_decimal);
$new_hex .= sprintf('%02.2s', $new_hex_component);
}
return $new_hex;
}
// Sanitize/Validate provided color variable
if (!isset($_GET['color']) || strlen($_GET['color']) != 6) {
header($_SERVER['SERVER_PROTOCOL'] . ' 400 Bad Request', true, 400);
exit(0);
}
if (file_exists( "cache/{$_GET['color']}.png" )) {
header( 'Content-Type: image/png' );
readfile( "cache/{$_GET['color']}.png" );
exit(0);
}
// Desired final size of image
$n_width = 50;
$n_height = 50;
// Actual size of source images
$width = 125;
$height = 125;
$image = imagecreatetruecolor($width, $height);
imagesavealpha($image, true);
imagealphablending($image, false);
$n_image = imagecreatetruecolor($n_width, $n_height);
imagesavealpha($n_image, true);
imagealphablending($n_image, false);
$black = imagecolorallocate($image, 0, 0, 0);
$transparent = imagecolorallocatealpha($image, 255, 255, 255, 127);
imagefilledrectangle($image, 0, 0, $width, $height, $transparent);
$layers = array();
$layers_processed = array();
$layers[] = array( 'src' => 'layer01.gif', 'level' => 0 ); // Border
$layers[] = array( 'src' => 'layer02.gif', 'level' => 35 ); // Background
$layers[] = array( 'src' => 'layer03.gif', 'level' => 100 ); // White Quotes
foreach ($layers as $idx => $layer) {
$img = imagecreatefromgif( $layer['src'] );
$processed = imagecreatetruecolor($width, $height);
imagesavealpha($processed, true);
imagealphablending($processed, false);
imagefilledrectangle($processed, 0, 0, $width, $height, $transparent);
$color = hexLighter( $_GET['color'], $layer['level'] );
$color = imagecolorallocate($image,
hexdec( $color{0} . $color{1} ),
hexdec( $color{2} . $color{3} ),
hexdec( $color{4} . $color{5} )
);
for ($x = 0; $x < $width; $x++)
for ($y = 0; $y < $height; $y++)
if ($black === imagecolorat($img, $x, $y))
imagesetpixel($processed, $x, $y, $color);
imagecolortransparent($processed, $transparent);
imagealphablending($processed, true);
array_push($layers_processed, $processed);
imagedestroy( $img );
}
foreach ($layers_processed as $processed) {
imagecopymerge($image, $processed, 0, 0, 0, 0, $width, $height, 100);
imagedestroy( $processed );
}
imagealphablending($image, true);
imagecopyresampled($n_image, $image, 0, 0, 0, 0, $n_width, $n_height, $width, $height);
imagealphablending($n_image, true);
header( 'Content-Type: image/png' );
imagepng( $n_image, "cache/{$_GET['color']}.png" );
imagepng( $n_image );
// Free up memory
imagedestroy( $n_image );
imagedestroy( $image );
我自己没有尝试过,但是您可以查看 GD 库中的函数imagecolorset()它具有类似颜色填充的效果,可以帮助处理白色背景。
您可以尝试使用 imagefilter 功能http://lv.php.net/imagefilter - 但这不会让您直接访问用另一种颜色替换一种颜色,只需更改 r/g/b 组件。
可以使用 imagesetpixel http://nl2.php.net/imagesetpixel来设置新的像素值来实现非常低级的解决方案。
缓慢但确定的方法,迭代每个像素。
function ReplaceColour($img, $r1, $g1, $b1, $r2, $g2, $b2)
{
if(!imageistruecolor($img))
imagepalettetotruecolor($img);
$col1 = (($r1 & 0xFF) << 16) + (($g1 & 0xFF) << 8) + ($b1 & 0xFF);
$col2 = (($r2 & 0xFF) << 16) + (($g2 & 0xFF) << 8) + ($b2 & 0xFF);
$width = imagesx($img);
$height = imagesy($img);
for($x=0; $x < $width; $x++)
for($y=0; $y < $height; $y++)
{
$colrgb = imagecolorat($img, $x, $y);
if($col1 !== $colrgb)
continue;
imagesetpixel ($img, $x , $y , $col2);
}
}
我不知道任何现成的功能。但我想你可以遍历图像的每个像素并改变它的颜色......