对此我绝对会发疯,所以请,任何建议都将受到欢迎。
我正在运行带有两个加密表的 SQL Server 2016:
hr_client
[id] [int] IDENTITY(1,1) NOT NULL,
[employee_id] [nvarchar](20) NULL,
[honorific] [nvarchar](20) COLLATE Latin1_General_BIN2 ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Randomized, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[first_name] [nvarchar](60) COLLATE Latin1_General_BIN2 ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Randomized, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[last_name] [nvarchar](60) COLLATE Latin1_General_BIN2 ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Randomized, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[gender] [char](1) COLLATE Latin1_General_BIN2 ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Deterministic, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[date_of_birth] [date] ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Deterministic, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[national_insurance] [nvarchar](9) COLLATE Latin1_General_BIN2 ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Randomized, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[start_date] [date] ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Deterministic, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[end_date] [date] ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Deterministic, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[position] [int] ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Deterministic, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[department] [int] ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Deterministic, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[manager] [nvarchar](20) COLLATE Latin1_General_BIN2 ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Deterministic, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[grade] [nvarchar](20) COLLATE Latin1_General_BIN2 ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Deterministic, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[salary] [decimal](10, 2) ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Deterministic, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[status] [int] NULL,
[modify_date] [datetime] NULL,
[user_modify] [nvarchar](20) NULL,
[active] [bit] NULL,
[type] [nvarchar](20) NULL
hr_grade
[id] [int] IDENTITY(1,1) NOT NULL,
[grade_id] [nvarchar](20) NULL,
[description] [nvarchar](30) NULL,
[min_rate] [decimal](10, 2) ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Randomized, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[max_rate] [decimal](10, 2) ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Randomized, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[overtime_1] [decimal](5, 2) ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Randomized, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[overtime_2] [decimal](5, 2) ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = [EXAMPLE_KEY_NAME], ENCRYPTION_TYPE = Randomized, ALGORITHM = 'AEAD_AES_256_CBC_HMAC_SHA_256') NULL,
[modify_date] [datetime] NULL,
[user_modify] [varchar](20) NULL,
[comments] [varchar](max) NULL,
[status] [int] NULL,
[active] [bit] NULL,
[type] [nvarchar](20) NULL,
[position] [int] NULL,
我已经设置了 Column Master 和 Column Encryption Keys(当前存储在 SQL Server 上)。我还设置了存储过程以从这两个表中插入和选择数据。数据按预期加密,并且可以使用存储过程插入和返回数据(所有工作都可以直接在 SSMS 中正常工作)。
为了访问数据,我创建了一个运行在我们内部 IIS Web 服务器上的 ASP MVC 应用程序。该应用程序的目标是 4.6.1,我使用 LinqToSql dbml 进行 SQL 连接和命令。连接字符串如下:
Data Source=EXAMPLE_IP;Column Encryption Setting=enabled;Initial Catalog=hr;Persist Security Info=True;User ID=EXAMPLE_USER;
数据可以毫无问题地插入到 hr_grade 表中并从中选择。
但是,我只能从 hr_client 表中选择,并且 INSERT(直接或通过存储过程)因以下错误而失败:
Operand type clash:
nvarchar(4000) encrypted with (
encryption_type = 'RANDOMIZED',
encryption_algorithm_name = 'AEAD_AES_256_CBC_HMAC_SHA_256',
column_encryption_key_name = 'EXAMPLE_KEY_NAME',
column_encryption_key_database_name = 'hr'
) is incompatible with nvarchar(20) encrypted with (
encryption_type = 'RANDOMIZED',
encryption_algorithm_name = 'AEAD_AES_256_CBC_HMAC_SHA_256',
column_encryption_key_name = 'EXAMPLE_KEY_NAME',
column_encryption_key_database_name = 'hr')
现在我能看到的唯一明显区别是 hr_client 表有 NVARCHAR 列,我的应用程序似乎不喜欢这些列。
有什么想法/建议吗?