2

当我触摸布局时，图像没有改变。它是动态的，我已将其添加到布局中。这是我创建动态布局的完整代码

        ID = 1;
        Display display = getWindowManager().getDefaultDisplay();
        Point size = new Point();
        display.getSize(size);
        width = size.x;
        height = size.y;
        Log.i("VRV", "Width :: " + width);
        Log.i("VRV", "height :: " + height);
        mWidth = width /    32;
        Log.i("VRV", "mWidth :: " + mWidth);
        int minHeight1 = height / 10;
        int mHeight = height - (int) (minHeight1 * 0.9);
        int minHeight = mHeight / 10;
        Log.i("VRV", "minHeight is ::" + minHeight);
        mAddingValue = (int) (minHeight * 0.9) + (int) (minHeight * 1);
        mHeaderLayout.getLayoutParams().height = (int) (minHeight * 2);
        mFooterLayout.getLayoutParams().height = (int) (minHeight * 2);
        mLinearLayout.getLayoutParams().height = (int) (minHeight * 6);
        mLinearLayout.setOnTouchListener(onTouchListener);

        connect(getIntent().getStringExtra("DEVICENUM"));
        ArrayList<String> list = new ArrayList<String>();
        ArrayList<Integer> jList = new ArrayList<>();
        for (int i = 0; i < 209; i++) {
            int rowno = i / 30;
            int col = i % 7;
            int j1 = (rowno * 100) + col;
            if (list.contains("" + j1)) {
                Log.d("VRV13", " design new  " + i);
                jList.add(i + 1);
            }
        }
        Log.i("VRV", "list.toString() :: " + jList.toString());

        for (int i = 0; i < 7; i++) {
            LinearLayout linearLayout = new LinearLayout(Drawingletters.this);
            linearLayout.setLayoutParams(new LinearLayout.LayoutParams(ViewGroup.LayoutParams.MATCH_PARENT, mWidth));
            linearLayout.setHorizontalGravity(Gravity.CENTER_HORIZONTAL);
            mViewList.add(linearLayout);
            for (int j = 0; j < 30; j++) {
                mView = new ImageView(Drawingletters.this);
                mView.setId(ID + j);
                mView.setLayoutParams(new LinearLayout.LayoutParams(mWidth, mWidth));
                Log.i("VRV", "list.contains(ID) :: " + ID + " ==> " + list.contains(ID));
                if (jList.contains(ID + j)) {
                    mView.setTag(1);
                    mView.setImageResource(R.drawable.round_white);
                } else {
                    mView.setTag(0);
                    mView.setImageResource(R.drawable.round_gray);
                }

                mView.setPadding(1, 1, 1, 1);
                mTextList.add(mView);
                linearLayout.addView(mView);
            }
            ID = ID + 30;
            mLinearLayout.addView(linearLayout);
        }

这段代码使我的布局看起来像这样 在此处输入图像描述

当我触摸或拖动它时，我将其设置为白色圆形图像。那么布局应该是这样的

在此处输入图像描述

在此，当我拖动布局时，白色图像根据 xy 坐标显示，当我单击单个白色图像时，它会消失（不完全消失，因为我将灰色圆形图像设置为它。但我的主要问题是当我单击在单个灰色圆形图像上，图像没有改变（只有当我拖动时它才会改变）。我想改变触摸图像并拖动两者。这是我的 onTouchListner 代码

View.OnTouchListener onTouchListener = new View.OnTouchListener() {
    @Override
    public boolean onTouch(View v, MotionEvent event) {
        int y = (int) event.getY();
        int x = (int) event.getX();
        if (y / mWidth < 7 && y / mWidth > -1) {
            ViewGroup viewGroup = mViewList.get(y / mWidth);
            ImageView mText = (ImageView) viewGroup.getChildAt(x / mWidth);
            if (mText != null) {
                if (isTouched && event.getAction() == MotionEvent.ACTION_UP) {
                    isTouched = false;
                    Log.i("VRV", "onTouchEvent mText.getId() :: " + mTextList.get(mText.getId() - 1).getTag());
                    mText.setImageResource(R.drawable.round_gray);
                    mText.setTag(1);
                    Log.i("VRV", "onTouchEvent mText.getId() :: " + mText.getId());
                    mTextList.get(mText.getId()-1).setTag(1);
                    return true;
                } else{
                    isTouched = true;
                    isTouchedenable = false;
                    mText.setImageResource(R.drawable.round_white);
                    mText.setTag(0);
                    Log.i("VRV", "onTouchEvent mText.getId() :: " + mText.getId());
                    mTextList.get(mText.getId()-1).setTag(0);
                }
            }
        }
        return true;
    }
};

请在这件事上给予我帮助

4

0 回答 0