0

我有以下数据

CREATE TABLE [dbo].[Test](
    [CustId] [int] NULL,
    [Spend] [money] NULL,
    [TimeOdSpent] [datetime] NULL,
    [ID] [int] IDENTITY(1,1) NOT NULL
) ON [PRIMARY]

GO
SET IDENTITY_INSERT [dbo].[Test] ON 
GO

INSERT [dbo].[Test] ([CustId], [Spend], [TimeOdSpent], [ID]) 
VALUES (11, 400.0000, CAST(N'2016-10-27 10:00:00.000' AS DateTime), 1)

INSERT [dbo].[Test] ([CustId], [Spend], [TimeOdSpent], [ID]) 
VALUES (11, 200.0000, CAST(N'2016-10-27 11:00:00.000' AS DateTime), 2)

INSERT [dbo].[Test] ([CustId], [Spend], [TimeOdSpent], [ID]) 
VALUES (11, 400.0000, CAST(N'2016-10-28 09:00:00.000' AS DateTime), 3)

INSERT [dbo].[Test] ([CustId], [Spend], [TimeOdSpent], [ID]) 
VALUES (11, 500.0000, CAST(N'2016-10-28 16:00:00.000' AS DateTime), 4)
GO
SET IDENTITY_INSERT [dbo].[Test] OFF

预期结果应该是这样的

1   2016-10-27 11:00:00.000 600
2   2016-10-28 09:00:00.000 1000
3   2016-10-28 16:00:00.000 900

我想找出在 24 小时内花费总计 > 500 的实例。试图写一个没有运气的窗口查询

4

2 回答 2

0

您可以查询如下：

Select * from (
    Select *, Sm = sum(spend) over(partition by convert(date,timeofuse)) from #customer
) a
Where Sm > 500
于 2017-08-01T19:52:16.467 回答
0

这就是我一直在寻找的东西。我使用了 AdventureWorks 的 Sales.SalesOrderHeader 表，而不是上面的简单表

  ;WITH cte1 as
(
select 
LAG(ShipDate) OVER(PARTITION By SAlesPersonId ORDER BY ShipDate) ShipDateBefore,ShipDate, SalesPersonID,SubTotal,CAST(ShipDate as Date) Date
from Sales.SalesOrderHeader 
where CAST(ShipDate as DATE)<'20080710' and SalesPersonID IS NOT NULL
),cte2 as
(Select * ,DATEDIFF(ss,ShipDateBefore,ShipDate) as DiffinDays
from cte1
), cte3 as (
select * ,SUM(DiffinDays) OVER(Partition BY SalesPersonId ORDER BY ShipDate ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) as RunningTime
from cte2
),cte4 as
(select 
*,ISNULL(CAST((RunningTime  / 86400.00) AS INT),0) Cycle
FROM cte3
)
SELECT 
SalesPersonID ,SUM(SubTotal)Total,MIN(ShipDate)DurationStart,MAX(ShipDate)DurationStart
from cte4

GROUP by SalesPersonID,Cycle 
Having SUM(SubTotal) > 100000.00
于 2017-08-06T22:37:10.060 回答