groovy - 为什么 groovy 每个函数在另一个函数内部不迭代

Question

为什么 groovy .each 函数只有一次迭代，而它位于另一次迭代中，如下面的代码所示？

代码：

@Grab('com.xlson.groovycsv:groovycsv:1.1')
import static com.xlson.groovycsv.CsvParser.parseCsv
import groovy.xml.MarkupBuilder
import groovy.xml.StreamingMarkupBuilder
def input = "input.xml"
def xml = new XmlSlurper().parse(input)
df = new FileReader("file.csv")
def writer = new StringWriter()
def data = parseCsv(df, readFirstLine: true)
new MarkupBuilder(writer).root {
    xml.children().each {
        it.attributes()
        println ("Here I am")
        data.eachWithIndex { row,id->                     
            println ("This line should be iterated all time") // but iterated only one time             
        }
    }
}

输出是这样的，

    Here I am
    This line should be iterated all time
    This line should be iterated all time
    This line should be iterated all time
    Here I am
    Here I am

预期输出：

Here I am
This line should be iterated all time
This line should be iterated all time
This line should be iterated all time
Here I am
This line should be iterated all time
This line should be iterated all time
This line should be iterated all time
Here I am
This line should be iterated all time
This line should be iterated all time
This line should be iterated all time

Answer 1

那是因为parseCsv返回一个Iterator，而不是一个Iterable：

请参阅groovycsv 库的源代码：

static Iterator parseCsv(Map args = [:], String csv) {
    new CsvParser().parse(args, csv)
}