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我正在寻找打印架构中所有物化视图所依赖的关系的架构和名称：

select c.relname, d.classid, d.objid,
  pg_describe_object(
    d.classid, d.objid, d.objsubid)
from pg_class c
  join pg_namespace n on c.relnamespace = n.oid
  left join pg_depend d on c.oid = d.objid
where n.nspname = 'direct' and d.deptype = 'n'

这给出了类似的东西：

        relname         | relname | classid | objid |                pg_describe_object                 
------------------------+---------+---------+-------+---------------------------------------------------
 cases                  |         |    2618 | 33736 | rule _RETURN on materialized view case_categories
 benefit_investigations |         |    2618 | 33928 | rule _RETURN on materialized view bi_intervals

返回的描述给出了一些提示，但它不包含关系的模式。如何获得实际的依赖模式和名称？[注意我使用的是 postgres 9.6]

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2 回答 2

2

干得好：

SELECT DISTINCT view_cs.nspname, view_c.relname, tab_cs.nspname, tab_c.relname
FROM pg_depend view_d
JOIN pg_class view_c ON view_c.oid = view_d.refobjid AND view_c.relkind = 'm'
JOIN pg_type view_ct ON view_ct.oid = view_c.reltype
JOIN pg_namespace view_cs ON view_cs.oid = view_ct.typnamespace
JOIN pg_depend tab_d ON tab_d.objid = view_d.objid
JOIN pg_class tab_c ON tab_c.oid = tab_d.refobjid AND tab_c.relkind = 'r'
JOIN pg_type tab_ct ON tab_ct.oid = tab_c.reltype
JOIN pg_namespace tab_cs ON tab_cs.oid = tab_ct.typnamespace
WHERE view_d.deptype = 'n'

诀窍是你必须JOIN pg_depend两次——一次用于视图规则关系，一次用于规则表关系。

于 2017-07-28T19:44:35.097 回答
1

添加

AND view_c.relname != tab_c.relname

@Boris 接受的答案的 WHERE 语句，以避免显示表对自身的依赖性

于 2021-05-20T22:38:21.310 回答