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我正在研究 GraphStream 库。现在，当我运行我的程序时，它会为我的图表打开新窗口并为我的图表打开单独的窗口。我试图创建一个JFrame并添加JPanel到JFrame，毕竟我试图将图形添加到我的JPanel但它说图形对象不是一个组件。

这是我的代码：

import java.awt.BorderLayout;
import java.awt.EventQueue;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Statement;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.border.EmptyBorder;

import org.graphstream.graph.*;
import org.graphstream.graph.implementations.*;

public class GraphExplore {
    static Connection conn2;
    static String result, result2;
    static JFrame frame;
    static JPanel panel;

    public static void main(String args[]) throws SQLException {
        EventQueue.invokeLater(new Runnable() {
            public void run() {
                try {
                    showData();
                } catch (SQLException e) {
                    e.printStackTrace();
                }
            }
        });
    }

    private static void showData() throws SQLException {

        JFrame frame = new JFrame();
        frame.setVisible(true);
        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        frame.setBounds(30, 50, 1300, 600);
        panel = new JPanel();
        panel.setBorder(new EmptyBorder(5, 5, 5, 5));
        panel.setLayout(new BorderLayout(0, 0));
        frame.setContentPane(panel);

        Graph graph = new SingleGraph("tutorial 1");
        graph.setAutoCreate(true);
        graph.setStrict(false);
        graph.display();

        // panel.add(graph);

        try {
            Class.forName("org.h2.Driver");
            conn2 = DriverManager.getConnection("jdbc:h2:file:G:/hs_data/h2_db/test", "sa", "sa");

        } catch (Exception e) {
            e.printStackTrace();
        }
        Statement stmt2 = conn2.createStatement();
        ResultSet rs2 = stmt2.executeQuery("SELECT ANUMBER,BNUMBER,DATETIME FROM TEST");
        while (rs2.next()) {
            result = rs2.getString("ANUMBER");
            result2 = rs2.getString("BNUMBER");
            graph.addNode(result);
            graph.addNode(result2);
            int i;
            for (i = 0; i < 200; i++)
                graph.addEdge("string" + i, result, result2);
            // JOptionPane.showMessageDialog(null, i);
        }

        for (Node node : graph) {
            node.addAttribute("ui.label", node.getId());
        }

    }

}

该程序为两者jframe和图形打开单独的窗口。我想将我的图表显示到我的JFrameorJPanel中。关于如何做到这一点的任何想法？我看过这个链接，但它并没有很好地解释我。

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1 回答 1

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如图形可视化：高级视图：将查看器集成到您的 GUI中所示，“您需要自己创建查看器。” 此外，在构建框架setVisible() 后调用。

它显示错误frame.add(view)。

看起来引用的教程有点过时了。该Viewer方法addDefaultView()现在返回 a ViewPanel，可以将其添加到 a Container。在下面的完整示例中，在封闭的JPanel有上设置了边框GridLayout，并将其panel添加到框架中。还要注意需要panel通过覆盖来提供首选大小getPreferredSize()。调整窗口大小以查看效果。

图片

import java.awt.*;
import javax.swing.*;
import javax.swing.border.*;
import org.graphstream.graph.*;
import org.graphstream.graph.implementations.*;
import org.graphstream.ui.swingViewer.*;
import org.graphstream.ui.view.*;

/** @see https://stackoverflow.com/a/45055683/230513 */
public class GraphSwing {

    public static void main(String args[]) {
        EventQueue.invokeLater(new GraphSwing()::display);
    }

    private void display() {
        JFrame frame = new JFrame();
        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        JPanel panel = new JPanel(new GridLayout()){
            @Override
            public Dimension getPreferredSize() {
                return new Dimension(640, 480);
            }
        };
        panel.setBorder(BorderFactory.createLineBorder(Color.blue, 5));
        Graph graph = new SingleGraph("Tutorial", false, true);
        graph.addEdge("AB", "A", "B");
        Node a = graph.getNode("A");
        a.setAttribute("xy", 1, 1);
        Node b = graph.getNode("B");
        b.setAttribute("xy", -1, -1);
        Viewer viewer = new Viewer(graph, Viewer.ThreadingModel.GRAPH_IN_GUI_THREAD);
        ViewPanel viewPanel = viewer.addDefaultView(false);
        panel.add(viewPanel);
        frame.add(panel);
        frame.pack();
        frame.setLocationRelativeTo(null);
        frame.setVisible(true);
    }
}
于 2017-07-12T10:54:43.417 回答