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在过去的几个小时里,我一直在尝试实现 Strassen 的矩阵乘法算法,并且在获得正确的产品时遇到了麻烦。我认为我的辅助函数之一(helpSub、createProd、helpProduct)可能是我的 strass2 函数的问题或格式(命令顺序等)。任何提示都会受到欢迎,因为我完全被难住了。我一直在使用两个 4 x 4 矩阵作为测试矩阵。我已经尝试了很多我在互联网上看到的 p1-p7 和 c1-c4 变体,但似乎都没有。下面是我创建的课程。

 /* @author williamnewman

public class strassen2 {

//Main Strassen multiplication function
//BASE CASE:
int [][] strass2(int[][] x, int[][]y){
    if(x.length == 1 && y.length == 1){
        System.out.println("Donezo");
        int [][] nu = new int[1][1];
        nu[0][0] = x[0][0] * y[0][0];
        return nu;

    }
    else{
   int[][] a,b,c,d,e,f,g,h;
   int dim = x.length/2;

//Dividing two matrices into 8 sub matrices
  System.out.println("A<B<C");
   a = helpSub(0,0,x);
   C(a);
   b = helpSub(0,dim,x);

   C(b);
   c = helpSub(dim,0,x);
   C(c);
   d = helpSub(dim,dim,x);
   C(d);
   e = helpSub(0,0,y);
   C(e);
   f = helpSub(0,dim,y);
   C(f);
   g = helpSub(dim,0,y);
   C(g);
   h = helpSub(dim,dim,y);
   C(h);

   int[][] p1,p2,p3,p4,p5,p6,p7;


//Creating p1-p7
   /
   p1 = strass2(a,subtract(f,h));
   p2 = strass2(h, add(a,b));
   p3 = strass2(e,add(c,d));
   p4 = strass2(d,subtract(g,e));
   p5 = strass2(add(a,d),add(e,h));
   p6 = strass2(subtract(b,d),add(g,h));
   p7 = strass2(subtract(a,c),add(e,f));
   int [][] prod;
   int [][] c1,c2,c3,c4;

//Creating c1-c4
   c1 = subtract(add(p6,p5),subtract(p4,p2));
   c2 = add(p1,p2);
   c3 = add(p3,p4);
   c4 = subtract(add(p1,p5),subtract(p3,p7));
   C(c1);
   System.out.println("C1::");
   C(c2);
   System.out.println("C2::");
   C(c3);
   System.out.println("C3::");
   C(c4);
   System.out.println("C4::");
//CREATES PRODUCT MATRIX
   prod = createProd(c1,c2,c3,c4);
   return prod;

    }




}

//Creates product matrix from c1-c4
int[][] createProd(int[][] c1, int[][] c2, int[][] c3, int[][] c4){
    int[][] product = new int[c1.length*2][c1.length*2];
    int mid = c1.length;
    int fin = c1.length * 2;
    helpProduct(0,0,mid,mid,product,c1);
    helpProduct(0,mid,mid,fin,product,c2);
    helpProduct(mid,0,fin,mid,product,c3);
    helpProduct(mid,mid,fin,fin,product,c4);

     System.out.println();
    System.out.println("PRODUCT::!:");
    C(product);
    return product;



}

    //Helper function to create larger matrix from submatrices
void helpProduct(int x, int y, int z1, int z2,int[][] product, int[][] a1){
    int indR = 0;
    int indC = 0;
    for(int i = x; i < z1; i++){
        indC = 0;
        for(int j = y; j < z2; j++){
            product[i][j] = a1[indR][indC];
            indC++;
        }
        indR++;
    }
}


    int[][] helpSub(int x, int y, int[][] mat){
    int[][] sub = new int[mat.length/2][mat.length/2];
    for(int i1 = 0, i2=x; i1 < (mat.length/2); i1++, i2++)
    for(int j1 = 0, j2=y; j1<(mat.length/2); j1++, j2++)
    {
            sub[i1][j1] = mat[i2][j2];
                           // System.out.println(sub[i1][j1]);
    }
    return sub;
}



//Normal Matrix Multiplication Function
int[][] multiply(int[][]a,int[][]b){
    MM nu = new MM(a,b);
    return nu.product;
}

    //Adds one matrix to the next
int[][] add(int[][]a, int[][]b){
    int [][] nu = new int[a.length][a[0].length];
    for(int i = 0; i < a.length; i++){
        for(int j = 0; j < a[i].length;j++){
            nu[i][j] = a[i][j] + b[i][j];
        }
    }
    return nu;
}

//Subtracts second matrix from the first
int[][] subtract(int[][] a, int[][] b){
    int [][] sub = new int[a.length][a.length];
    //System.out.println("made it");
    for(int i = 0; i < a.length; i++){
        for(int j = 0; j < a[i].length;j++){
            sub[i][j] = a[i][j] - b[i][j];
        }
    }
    return sub;
}
//Prints the matrix
 void C(int[][] product){
    for(int i = 0; i <product.length; i++){
        for(int j = 0; j < product[i].length; j++){
            System.out.print(product[j][i]  + " ");

        }
        System.out.println();
    }
}
}

如果有任何令人困惑的地方,请告诉我,我会更新问题!

这是主要功能::

      public static void main(String[] args) {
        int [][]a = {{1,2,3,4},
            {4,3,2,1},
            {1,2,3,4},
            {4,3,2,1}};

        int [][]b = {{3,4,5,6},
            {3,4,5,6},
            {5,4,3,2},
            {5,4,3,2}
        };
        MM a1 = new MM(a,b);
        a1.C();
        int[][] prod;
        System.out.println("----");
        strassen2 a2 = new strassen2();
        prod = a2.strass2(a,b);
        a2.C(prod);
    }

}

以下是目前的结果(预期结果是显示的第一个 4x4 矩阵,实际结果是显示的最后一个 4x4 矩阵):

EXPECTED:

44 40 36 32 
36 40 44 48 
44 40 36 32 
36 40 44 48 
----


ACTUAL::
70 78 50 42 
86 86 34 34 
30 38 30 38 
38 54 38 54 

我很确定我的 helpSub() 函数可以正常工作,因为它们产生了更正的啊。但是,我在 strass2 递归调用中使用的参数可能存在问题。很抱歉,如果它不够具体,我只是对此有点筋疲力尽,并且很好奇是否有人看到任何明显的问题。

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1 回答 1

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抱歉含糊不清,但似乎我已经解决了这个问题。我使用了这个网站上的公式来计算 p1-p7 和 c1-c4。([施特拉森矩阵乘法的公式][1]

[1]: http: //www.stoimen.com/blog/2012/11/26/computer-algorithms-strassens-matrix-multiplication/

实施这些公式后,产品矩阵几乎是正确的,但 4 或值已关闭。然后我将基本情况更改为当 x 和 y 的长度等于 2 时,这似乎纠正了 4 个关闭的值。对于那些好奇的人,这里是我为 strassen2 类修改的代码。

/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */
package pkg2a;

/**
 *
 * @author williamnewman
 */
public class strassen2 {

    int [][] strass2(int[][] x, int[][]y){
        if(x.length <= 2 && y.length <= 2){ //!!!! MODIFICATION HERE !!
            return multiply(x,y);

        }
        else{
       int[][] a,b,c,d,e,f,g,h;
       int dim = x.length/2;

      System.out.println("A<B<C");
       a = helpSub(0,0,x);
       //C(a);
       b = helpSub(0,dim,x);

       //C(b);
       c = helpSub(dim,0,x);
       //C(c);
       d = helpSub(dim,dim,x);
       //C(d);
       e = helpSub(0,0,y);
       //C(e);
       f = helpSub(0,dim,y);
       //C(f);
       g = helpSub(dim,0,y);
       //C(g);
       h = helpSub(dim,dim,y);
       //C(h);

       int[][] p1,p2,p3,p4,p5,p6,p7;
      // createSub(x,y,a,b,c,d,e,f,g,h);
      int[] s1,s2,s3,s4,s5,s6,s7,s8,s9,s10; 

      //MODIFICATION HERE
       p1 = strass2(a,subtract(f,h));
       p2 = strass2(add(a,b),h);
       p3 = strass2(add(c,d),e);
       p4 = strass2(d,subtract(g,e));
       p5 = strass2(add(a,d),add(e,h));
       p6 = strass2(subtract(b,d),add(g,h));
       p7 = strass2(subtract(a,c),add(e,f));
       int [][] prod;
       int [][] c1,c2,c3,c4;
       c1 = subtract(add(p5,p4),subtract(p2,p6));
       c2 = add(p1,p2);
       c3 = add(p3,p4);
       c4 = subtract(add(p1,p5),add(p3,p7));
       //C(c1);
       //System.out.println("C1::");
       //C(c2);
       //System.out.println("C2::");
       //C(c3);
       //System.out.println("C3::");
       //C(c4);
       //System.out.println("C4::");
       prod = createProd(c1,c2,c3,c4);
       return prod;

        }




    }

    int[][] createProd(int[][] c1, int[][] c2, int[][] c3, int[][] c4){
        int[][] product = new int[c1.length*2][c1.length*2];
        int mid = c1.length;
        int fin = c1.length * 2;
        helpProduct(0,0,mid,mid,product,c1);
        helpProduct(0,mid,mid,fin,product,c2);
        helpProduct(mid,0,fin,mid,product,c3);
        helpProduct(mid,mid,fin,fin,product,c4);

         System.out.println();
        System.out.println("PRODUCT::!:");
        //C(product);
        return product;



    }

        //Helper function to create larger matrix from submatrices
    void helpProduct(int x, int y, int z1, int z2,int[][] product, int[][] a1){
        int indR = 0;
        int indC = 0;
        for(int i = x; i < z1; i++){
            indC = 0;
            for(int j = y; j < z2; j++){
                product[i][j] = a1[indR][indC];
                indC++;
            }
            indR++;
        }
    }

    /*
        void createSub(int[][]x, int[][]y,int[][] a,int[][] b,int[][] c, int[][] d, int[][] e, int[][] f, int [][] g, int[][] h){
       int div1R = x.length/2;
       int div1C = div1R;
       int div2R = div1R;
       int div2C = div1R;
       a = helpSub(0,0,div1R,div1C,x);
      // c(a);
       b = helpSub(0,div1C,div1R,x[0].length,x);
       //c(b);
       c = helpSub(div1R,0,x.length,div1C,x);
       //c(c);
       d = helpSub(div1R,div1C,x.length,x[0].length,x);
       //c(d);
       e = helpSub(0,0,div2R,div2C,y);
       //c(e);
       f = helpSub(0,div2C,div2R,y[0].length,y);
      // c(f);
       g = helpSub(div2R,0,y.length,div2C,y);
       //c(g);
       h = helpSub(div2R,div2C,y.length,y[0].length,y);
      // c(h);


    }
        */
        int[][] helpSub(int x, int y, int[][] mat){
        int[][] sub = new int[mat.length/2][mat.length/2];
        for(int i1 = 0, i2=x; i1 < (mat.length/2); i1++, i2++)
        for(int j1 = 0, j2=y; j1<(mat.length/2); j1++, j2++)
        {
                sub[i1][j1] = mat[i2][j2];
                               // System.out.println(sub[i1][j1]);
        }
        return sub;
    }


    int[][] multiply(int[][]a,int[][]b){
        MM nu = new MM(a,b);
        return nu.product;
    }

        //Adds one matrix to the next
    int[][] add(int[][]a, int[][]b){
        int [][] nu = new int[a.length][a[0].length];
        for(int i = 0; i < a.length; i++){
            for(int j = 0; j < a[i].length;j++){
                nu[i][j] = a[i][j] + b[i][j];
            }
        }
        return nu;
    }

    //Subtracts second matrix from the first
    int[][] subtract(int[][] a, int[][] b){
        int [][] sub = new int[a.length][a.length];
        //System.out.println("made it");
        int rows = a.length;
        int columns = a[0].length;
        for(int i = 0; i < rows; i++){
            for(int j = 0; j < columns;j++){
                sub[i][j] = a[i][j] - b[i][j];
            }
        }
        return sub;
    }

     void C(int[][] product){
        for(int i = 0; i <product.length; i++){
            for(int j = 0; j < product[i].length; j++){
                System.out.print(product[i][j]  + " ");

            }
            System.out.println();
        }
    }
}
于 2017-07-12T03:36:11.463 回答