因此,对于上下文,我想让您知道我到目前为止所了解的内容:
指令执行后调用中断处理并设置中断主机使能标志。
中断处理由多个“中断例程”组成(对于gameboy,它有Vblank、LCD stat、计时器、手柄和串行)。
CPU 需要根据 IE 标志和 IF 标志上设置的值来处理每个中断。
中断例程具有优先级(与我的问题并不真正相关)。
中断例程必须有开始和结束
因此,查看中断例程,它首先将在例程结束后应该保留的寄存器值推入堆栈指针。现在它总是有 reti 指令,我认为它总是一个中断例程的结束,它应该在处理中断之前弹出下一条指令的地址。
我想知道是否:
reti 指令在每个中断例程中只出现一次并且只出现在最后,这是一个“标准”吗?因为这是我可以确定是否会结束阅读进一步说明的唯一方法,
它使用 reti 而不是 ret 因为我们想要断言 ime 标志仍然处于启用状态,因此可以继续检查是否需要提供任何其他中断,
在中断处理开始之前,我需要将下一条指令的地址显式推送到堆栈指针中,因为没有汇编指令指示在中断处理开始之前将其推送。这是为了在中断结束时进行 reti 指令。
编辑:
因此,为了提供有关我的问题的更多背景信息,我决定发布我的指令周期代码。
在 CPU.c 中
#include "InteruptHandler.c"
void main(){
while(){ //No proper argument yet. for fetch-decode-execute cycle
opcode = fetchInstruction();
decodeandExecuteInstruction(opcode); //Lets say an instruction is executed and it enabled the IME_flag. that is IME_flag = ENABLED
//Check if ime_flag is enabled. processInterupt if true.
isInteruptEnabled() ? processInterupts(): 0; //This would fall true.
}
}
在 InteruptHandler.c 中
processInterupts(){
opcode;
bitmask = 0x01;
//Check each bit for interupt. Bitmask will go 0x00 if the value 0x80 is shifted by 1
for(; bitmask ; bitmask = bitmask << 1){
//CHeck if IE and IF flag for corresponding interupt is set. process interupt if set
IE_flag & bitmask ? (IF_flag & bitmask ? determineInterupt(bitmask) : 0) : 0;
}
}
determineInterupt(bitmask){
//push the next instruction address to stack pointer
push(PC);
//Set PC into corresponding interupt address
//code below is my problem. I stumbled upon how would I end this function and I came up to determining when an interupt routine ends.
//I came up with the reti function.
//But after realizing that I already set the PC somewhere above this code, I just need to discard this code and let the main function do its instruction cycling.
//Thanks to @duskwuff for pointing that out.
//I just added some code to end the bitmask checking when it sees 1 interupt request and is most priotiry.
//Also thanks to @Ped7g for giving me more information about the complexity of interupt handling. I'm not yet seeing where I should implement those. There are still so many thing to implement and yet to know when this excatly can happen.
//My question has been answered nevertheless, which is to end a function code blocks that I discarded at the end :)
//process the corresponding interupt
do{
opcode = fetchInstruction();
decodeandexecuteInstruction(opcode);
}while (opcode != RETI)
}