select Document_id, Document_date, sum(document_money)
from documents
group by Docuemnt_id, Docuement_date;
第一个查询检索以下结果:
1 01-FEB-2017 10000
2 02-FEB-2017 20000
3 03-FEB-2017 10000
查询 #2:
select document_id, Document_date, document_money, document_details
from documents ;
结果:
1 01-FEB-2017 5000 rentment
1 01-FEB-2017 5000 food
2 02-FEB-2017 10000 car
2 02-FEB-2017 10000 house
3 03-FEB-2017 7000 mobiles
3 03-FEB-2017 3000 drinks
如何创建一个查询,提供给我 document_no、the_date、金额和详细信息,如下所示:
1 01-FEB-2017 10000 rentment
1 01-FEB-2017 10000 food
2 02-FEB-2017 20000 car
2 02-FEB-2017 20000 house
3 03-FEB-2017 10000 mobiles
3 03-FEB-2017 10000 drinks