1

我需要一些帮助来序列化一个实体以通过 Akka Remote 发送它。

这是序列化程序类：

@Override
public void toBinary(Object o, ByteBuffer buf)  {

    byte[] bytes = null;
    ByteArrayOutputStream bos = null;
    ObjectOutputStream oos = null;
    try {
        bos = new ByteArrayOutputStream();
        oos = new ObjectOutputStream(bos);
        oos.writeObject(o);
        oos.flush();
        bytes = bos.toByteArray();
    }
    catch(Exception e){
        //System.out.println(e.getStackTrace());
        e.printStackTrace();
    }
    buf.put(bytes);
}

@Override
    public Object fromBinary(ByteBuffer buf, String manifest) {
        Object obj = null;
        ByteArrayInputStream bis = null;
        ObjectInputStream ois = null;

        try {
            bis = new ByteArrayInputStream(buf.array());
            ois = new ObjectInputStream(bis);
            obj = ois.readObject();
         }
        catch(Exception e){
            //System.out.println(e.getStackTrace());
            e.printStackTrace();
        }
        return obj;
    }

我在第 5 行得到以下异常

java.lang.UnsupportedOperationException
    at java.nio.ByteBuffer.array(ByteBuffer.java:994)
    at serializers.ExampleByteBufSerializer.fromBinary(ExampleByteBufSerializer.java:67)
    at akka.serialization.Serialization.deserializeByteBuffer(Serialization.scala:190)
    at akka.remote.MessageSerializer$.deserializeForArtery(MessageSerializer.scala:91)
    at akka.remote.artery.Deserializer$$anon$3.onPush(Codecs.scala:620)
    at akka.stream.impl.fusing.GraphInterpreter.processPush(GraphInterpreter.scala:499)
    at akka.stream.impl.fusing.GraphInterpreter.execute(GraphInterpreter.scala:401)
    at akka.stream.impl.fusing.GraphInterpreterShell.runBatch(ActorGraphInterpreter.scala:571)
    at akka.stream.impl.fusing.GraphInterpreterShell$AsyncInput.execute(ActorGraphInterpreter.scala:457)
    at akka.stream.impl.fusing.GraphInterpreterShell.processEvent(ActorGraphInterpreter.scala:546)
    at akka.stream.impl.fusing.ActorGraphInterpreter.akka$stream$impl$fusing$ActorGraphInterpreter$$processEvent(ActorGraphInterpreter.scala:725)
    at akka.stream.impl.fusing.ActorGraphInterpreter$$anonfun$receive$1.applyOrElse(ActorGraphInterpreter.scala:740)
    at akka.actor.Actor$class.aroundReceive(Actor.scala:513)
    at akka.stream.impl.fusing.ActorGraphInterpreter.aroundReceive(ActorGraphInterpreter.scala:650)
    at akka.actor.ActorCell.receiveMessage(ActorCell.scala:527)
    at akka.actor.ActorCell.invoke(ActorCell.scala:496)
    at akka.dispatch.Mailbox.processMailbox(Mailbox.scala:257)
    at akka.dispatch.Mailbox.run(Mailbox.scala:224)
    at akka.dispatch.Mailbox.exec(Mailbox.scala:234)
    at akka.dispatch.forkjoin.ForkJoinTask.doExec(ForkJoinTask.java:260)
    at akka.dispatch.forkjoin.ForkJoinPool$WorkQueue.runTask(ForkJoinPool.java:1339)
    at akka.dispatch.forkjoin.ForkJoinPool.runWorker(ForkJoinPool.java:1979)
    at akka.dispatch.forkjoin.ForkJoinWorkerThread.run(ForkJoinWorkerThread.java:107)

这是我发送给远程参与者的消息：

public class Message2Serialize implements Serializable {

    String nombre;

    public Message2Serialize(String nombre) {
        this.nombre = nombre;
    }

    public Message2Serialize() {
    }

    public String getNombre() {
        return nombre;
    }


    public void setNombre(String nombre) {
        this.nombre = nombre;
    }
}

奇怪的是它以一种方式工作，如果我们使用它发送消息，它在接收器中工作正常：

ActorSelection selection = getContext().system().actorSelection("akka://applicationremote@localhost:25521/user/actors.MessageReceiverActor");
selection.tell(message2Serialize, getSelf());

但是当我们使用 then 重播给发送者 actor 时， getSender().tell(m, getSelf());我们得到了异常。

我们正在使用 Java 1.8 和 akka-remote_2.11:2.5.3

提前致谢！罗德里

4

2 回答 2

0

通过更改此行 bis = newByteArrayInputStream(arr);：

byte[] arr = new byte[buf.remaining()];
buf.get(arr);
bis = new ByteArrayInputStream(arr);

它有效，但我不确定为什么。

于 2017-06-30T16:57:04.117 回答
0

javadoc 提取

@throw UnsupportedOperationException。如果此缓冲区不受可访问数组的支持

ByteBuffer 似乎没有完全初始化......此外，javadoc 还说明了该怎么做

在调用此方法之前调用 {@link #hasArray hasArray} 方法，以确保此缓冲区具有可访问的后备数组。

于 2017-06-27T21:03:41.780 回答