r - R- knitr:kable - 如何显示没有列名的表格？

Question

目前，我有这个数据框（PS）：

我显示此表的代码是：

kable(PS) %>%
kable_styling(bootstrap_options = c("striped", "hover", "condensed", "responsive"))

我想显示没有列名的表，如下所示：

问题是

1) 列名不能为空，尝试使用空名会得到不支持的结果

2）如果我转换数据框并删除列名，然后像这样使用 kable：

PS.mat <- as.matrix(PS)
colnames(PS.mat) <- NULL
kable(PS) %>%
kable_styling(bootstrap_options = c("striped", "hover", "condensed", "responsive"))

我收到以下错误

Error in kable_info$colnames[[length(kable_info$colnames)]] : attempt to select less than one element in integerOneIndex

我也尝试了以下参数但没有结果

kable(PS, col.names = NA) 

编辑1：

一个可重现的例子：

if (!require(pacman)) install.packages("pacman")
p_load("lubridate","knitr","kableExtra","scales")

Statistics <- c("AUM",
            "Minimum Managed Account Size",
            "Liquidity",
            "Average Margin / Equity",
            "Roundturns / $ Million / Year",
            "Incentive Fees",
            "Instruments Traded")
Value <- c("$30K","$30K","Daily","50%","6,933","25%","ES")
AI <- data.frame(Statistics,Value);
kable(AI) %>%
kable_styling(bootstrap_options = c("striped", "hover", "condensed", "responsive"))

Answer 1

根据您所需的输出格式，您可以使用这些功能。对于潘多克：

x = kable(AI, format="pandoc") %>%
    kable_styling(bootstrap_options = c("striped", "hover", "condensed", "responsive"))
cat(x[3:9], sep="\n")

对于 html：

x = kable(AI, format="html") %>%
    kable_styling(bootstrap_options = c("striped", "hover", "condensed", "responsive"))
gsub("<thead>.*</thead>", "", x)