java - 如何使用 javapoet 生成 Class 参数？

Question

我需要为枚举类生成下一个 java.class 参数：

    public enum ServiceType {

        //....
        private final Class<?> mClass; //<<how?

        ServiceType(final Class<?> clazz) {
            this.mClass = clazz;
        }

        public Class<?> getCurrentClass() {
            return mClass;
        }
        //...
    }

我没有找到 - 如何制作这个字段。

我生成此类的代码：

        File path = new File(Path.ROOT + ENUM_PATH);

        TypeSpec.Builder servicesEnumBuilder = TypeSpec.enumBuilder(ENUM_CLASS_NAME)
                .addModifiers(Modifier.PUBLIC);

        for (Map.Entry<String, String> entry: foundedServices.entrySet()) {
            servicesEnumBuilder.addEnumConstant(
                    entry.getKey().toUpperCase() + ENUM_SUFFIX,
                    TypeSpec.anonymousClassBuilder("$T", ClassName.get(entry.getValue() , entry.getKey())).build());
        }

        servicesEnumBuilder.addField(); //<< how add this field: private final Class<?> mClass;

Answer 1

你可以检查这个答案

应用于您的案例将是这样的：

    TypeName wildcard = WildcardTypeName.subtypeOf(Object.class);
    TypeName classOfAny = ParameterizedTypeName.get(
            ClassName.get(Class.class), wildcard);
    FieldSpec field = FieldSpec.builder(classOfAny, "mClass")  // You may consider using a constant here
            .addModifiers(Modifier.PRIVATE, Modifier.FINAL)
            .build();

    servicesEnumBuilder.addField(field);