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这是我当前的代码,但在转换为 BITMAPINFOHEADER 时会导致错误:

/* Create the bitmap */
BITMAPINFO bmpinfo;
ZeroMemory(&bmpinfo, sizeof(bmpinfo));
BITMAPV5HEADER bmpheader;
ZeroMemory(&bmpheader, sizeof(bmpheader));
bmpheader.bV5Size = sizeof(BITMAPV5HEADER);
bmpheader.bV5Width = width;
bmpheader.bV5Height = height;
bmpheader.bV5Planes = 1;
bmpheader.bV5BitCount = 32;
bmpheader.bV5Compression = BI_BITFIELDS;
bmpheader.bV5SizeImage = width*height*4;
bmpheader.bV5RedMask = 0x00FF0000;
bmpheader.bV5GreenMask = 0x0000FF00;
bmpheader.bV5BlueMask = 0x000000FF;
bmpheader.bV5AlphaMask = 0xFF000000;
bmpheader.bV5CSType = 0x57696e20; // LCS_WINDOWS_COLOR_SPACE
bmpheader.bV5Intent = LCS_GM_BUSINESS;
bmpinfo.bmiHeader = reinterpret_cast<BITMAPINFOHEADER>(bmpheader);
void* converted = NULL;
HDC screen = GetDC(NULL);
HBITMAP result = CreateDIBSection(screen, &bmpinfo, DIB_RGB_COLORS, &converted, NULL, 0);
ReleaseDC(NULL, screen);
// Image data filled here

我怎样才能成功地做到这一点?

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1 回答 1

3

BITMAPINFO不是一个真正的结构,它只是关于颜色映射如何跟随标题的文档。只需将您的BITMAPV5HEADER直接传递给 CreateDIBSection:

HBITMAP result = CreateDIBSection(screen, reinterpret_cast<BITMAPINFO *>(&bmpheader), DIB_RGB_COLORS, &converted, NULL, 0); 
于 2010-12-15T22:49:56.517 回答