0

我有两个部分函数f1，f2​​我想将它们组合成一个新的部分函数f，​​以便f.isDefinedAt(x)iff f1.isDefinedAt(x) || f2.isDefinedAt(x)。我是说

        --
       | f1(x) iff f1.isDefinedAt(x)  
       |
f(x) = |
       |
       | f2(x) iff  !f1.isDefinedAt(x) && f2.isDefinedAt(x)  
        --

f1有没有办法作曲f2？

4

2 回答 2

1

.orElse使用方法PartialFunction：

scala> val f1: PartialFunction[Int, Unit] = { case x if x > 0 => println(s"called f1 with $x") }
f1: PartialFunction[Int,Unit] = <function1>

scala> val f2: PartialFunction[Int, Unit] = { case x if x < 0 => println(s"called f2 with $x") }
f2: PartialFunction[Int,Unit] = <function1>

scala> (f1 orElse f2)(1)
called f1 with 1

scala> (f1 orElse f2)(-1)
called f2 with -1

scala> (f1 orElse f2)(0)
scala.MatchError: 0 (of class java.lang.Integer)
  at scala.PartialFunction$$anon$1.apply(PartialFunction.scala:253)
  at scala.PartialFunction$$anon$1.apply(PartialFunction.scala:251)
  at $anonfun$1.applyOrElse(<console>:11)
  at $anonfun$1.applyOrElse(<console>:11)
  at scala.runtime.AbstractPartialFunction$mcVI$sp.apply$mcVI$sp(AbstractPartialFunction.scala:36)
  at scala.runtime.AbstractPartialFunction$mcVI$sp.apply(AbstractPartialFunction.scala:36)
  at scala.runtime.AbstractPartialFunction$mcVI$sp.apply(AbstractPartialFunction.scala:28)
  at $anonfun$1.applyOrElse(<console>:11)
  at $anonfun$1.applyOrElse(<console>:11)
  at scala.PartialFunction$OrElse.apply(PartialFunction.scala:167)
  at scala.Function1$class.apply$mcVI$sp(Function1.scala:36)
  at scala.PartialFunction$OrElse.apply$mcVI$sp(PartialFunction.scala:164)
  ... 32 elided
于 2017-06-13T09:43:33.997 回答
1

使用PartialFunction's orElse

f1 orElse f2

于 2017-06-13T09:43:23.193 回答